Bourbaki

Exercise 33, § 1

Tag 02L9, permanent. Cite it as [Bourbaki, Tag 02L9].

Spectral Theories, II, p. 275

For every integer r⩾1r\geqslant 1, let Vr=V_r= det((xijx^j_i)1⩽i⩽r_{1\leqslant i\leqslant r})∈Z[x1,...,xr]\in \mathbf{Z}[x_1, . . . , x_r] denote the Vandermonde determinant (A, III, p. 99, example 11).0⩽j<r.^{0\leqslant j<r}

a) Let f1,...,frf_1, . . . ,f_r be functions indefinitely differentiable on R\mathbf{R}. For all real numbers x1<⋯<xrx_1<\cdots < x_r, there exist real numbers (t0,...,tr−1)(t_0, . . . , t_{r-1}) in [x1,xr][x_1, x_r] such that

det(fi(xj)f_i(x_j)) == 1!2! ⋯1(r−\cdots 1(r- 1)! Vr(x1,...,xr)V_r(x_1, . . . , x_r) det((fj(i)(ti)f_j^{(i)}(t_i))01⩽⩽ij<r⩽r_{01\leqslant\leqslant ij<r\leqslant r})

(cf. FVR, I, p. 48, Exercise 11).

b) Let rr be a positive integer and m1,...,mrm_1, . . . , m_r positive integers. Let

Δr=\Delta_r= det((ximjx_i^{m_j})1⩽i,j⩽r_{1\leqslant i,j\leqslant r})∈Z[x1,...,xr]\in \mathbf{Z}[x_1, . . . , x_r].

The polynomial Δr\Delta_r is divisible by VrV_r in Z[x1,...,xr]\mathbf{Z}[x_1, . . . , x_r]. Let Fr=Δr/VrF_r= \Delta_r/V_r. c) Let pp be a prime number. Suppose that

0⩽m1<m2<⋯<mr⩽p−1 0\leqslant m_1< m_2<\cdots < m_r\leqslant p-1

Let ξ1,...,ξr\xi_1,. . .,\xi_r be distinct pp-th roots of unity. One has

Fr(ξ1,...,ξr)≠0 F_r(\xi_1, . . . , \xi_r)\not= 0

(“Chebotarev theorem”; let ξ\xi be a primitive pp-th root of unity; one has Fr(ξ1,...,ξr)=P(ξ)F_r(\xi_1, . . . , \xi_r) = P(\xi ) where P∈Z[x]P\in \mathbf{Z}[x] is of degree ⩽p−1\leqslant p-1; from the irreducibility of cyclotomic polynomials, the condition Fr(ξ1,...,ξr)=0F_r(\xi_1, . . . , \xi_r) = 0 would imply that Fr(1,...,1)F_r(1, . . . ,1) is divisible by pp; using a) with xi→1x_i\rightarrow 1, prove that this is not the case.)

d) Let G=Z/pZG =\mathbf{Z}/p\mathbf{Z}. For every function f≠0f\not= 0 from G into C\mathbf{C}, one has

Card(Supp(ff)) ++ Card(Supp(f^\widehat{f}))⩾p+1\geqslant p+ 1.

e) For all non-empty subsets A and B in G such that

Card(A) + Card(B) ⩾p+1\geqslant p+ 1,

there exists f:G→Cf: G\rightarrow \mathbf{C} whose support is A and such that the support of f^\widehat{f} is B. (Consider first the case where Card(A) + Card(B) =p+1=p+ 1.)

f) Let A and B be arbitrary subsets of G. One has

Card(A +B+ B)⩾\geqslant inf(Card(A) + Card(B) −1,p-1, p)

(“Cauchy-Davenport theorem”; apply the previous question to (A,C)(A,C) and to (B,D)(B,D), where C and D are subsets of cardinal respectively p+1−p+ 1- Card(A) and p+1−p+ 1- Card(B), such that C∩DC\cap D has cardinal sup(Card(A) + Card(B) −p,1-p,1).)

g) Let (a1,...,a2p−1)(a_1, . . . , a_{2p-1}) be a family of elements of Fp\mathbf{F}_p. There exists a subset I⊂{1,...,2p−1}I\subset \{1, . . . ,2p-1\} of cardinal pp such that

∑i∈Iai=0 \sum_{i\in I}a_i= 0

This property is false in general for a family in Fp2p−2\mathbf{F}^{2p-2}_p. (Let 0⩽b1⩽⋯⩽⋯⩽b2p−1<p0\leqslant b_1\leqslant \cdots \leqslant \cdots \leqslant b_{2p-1}< p be integers whose reductions modulo pp form a permutation of (a1,...,a2p−1)(a_1, . . . , a_{2p-1}); treat directly the case where there exists ii such that ai=ai+p−1a_i=a_{i+p-1}, and apply the previous question in the contrary case.)

h) Let k⩾1k\geqslant 1 be an integer. Let ν⩾0\nu \geqslant 0 be the integer such that k=pνrk=p^{\nu}r where pp does not divide rr. Let us denote by γ\gamma the integer

{ν+1\{\nu + 1 if p⩾3p\geqslant 3

γ= \gamma =

ν+2\nu + 2 otherwise. If ℓ⩾4k\ell \geqslant 4k is an integer, then there exist integers (n1,...,nℓ)(n_1, . . . , n_{\ell}) such that pp does not divide all the nin_i and such that

n1k+⋯+nℓk≡0n^k_1+\cdots +n^k_{\ell}\equiv 0 mod.pγ. p^{\gamma}.

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