Bourbaki

Exercise 58, § 1

Tag 02LY, permanent. Cite it as [Bourbaki, Tag 02LY].

Spectral Theories, II, p. 294

For every nonzero real number λ\lambda, let μλ\mu_{\lambda} denote the discrete probability measure on R\mathbf{R} such that μλ(λ)=μλ(−λ)=12\mu_{\lambda}(\lambda ) =\mu_{\lambda}(-\lambda ) =\frac{1}{2}.

Fix λ∈]0,1[\lambda \in ]0,1[.

a) Put ν0=μ1\nu_0=\mu_1 and νn+1=μλn+1∗νn\nu_{n+1}=\mu_{\lambda^{n+1}}*\nu_n for every integer n⩾0n\geqslant 0. The sequence (νn)n∈N(\nu_n)_{n\in\mathbf{N}} converges to a probability measure νλ\nu_{\lambda} on R\mathbf{R}. The characteristic function of νλ\nu_{\lambda} is the function on R\mathbf{R} defined by

φλ(x)=∏n=0+∞\varphi_{\lambda}(x) =\prod_{n=0}^{+\infty} cos(λnx\lambda^nx).

b) The measure νλ\nu_{\lambda} is the unique positive measure ν\nu of total mass 1 on R\mathbf{R} such that

ν=12ℓ1(ν)+12ℓ2(ν) \nu =\frac{1}{2}\ell_1(\nu ) +\frac{1}{2}\ell_2(\nu )

where ℓ1\ell_1 (resp. ℓ2\ell_2) is the mapping x↦λx−1x\mapsto \lambda x-1 (resp. x↦λx+1x\mapsto \lambda x+ 1) of R\mathbf{R} into R\mathbf{R}.

c) If the measure νλ\nu_{\lambda} is not a measure of base Lebesgue measure, then νλ\nu_{\lambda} is singular with respect to Lebesgue measure. (Consider the Lebesgue decomposition of νλ\nu_{\lambda} with respect to Lebesgue measure, cf. INT, V, §5, no7^o7, th. 3.)

d) If 0<λ<120< \lambda <\frac{1}{2}, then the measure νλ\nu_{\lambda} is singular with respect to Lebesgue measure. e) If λ=12\lambda =\frac{1}{2}, then the measure νλ\nu_{\lambda} is equal to the uniform measure on [−2,2][-2,2]. If λ>1/2\lambda >1/2, the support of νλ\nu_{\lambda} is the interval [−(1−λ)−1,(1−λ)−1][-(1-\lambda )^{-1},(1-\lambda )^{-1}].

f) A Pisot number is a real algebraic integer xx such that all the conjugates y∈Cy\in \mathbf{C} of xx, other than xx, satisfy ∣y∣<1|y|<1. If λ−1\lambda^{-1} is a Pisot number, then the function φλ\varphi_{\lambda} does not tend to 0 at infinity. In particular, the measure νλ\nu_{\lambda} is singular with respect to Lebesgue measure.

g) There exists λ>1/2\lambda >1/2 such that νλ\nu_{\lambda} is singular with respect to Lebesgue measure.

Henceforth assume that φλ\varphi_{\lambda} does not tend to 0 at infinity, and put θ=1/λ\theta = 1/\lambda. For every real number xx, let ⟨x⟩\langle x\rangle denote the unique real number in [0,1[[0,1[ such that x−⟨x⟩∈Zx- \langle x\rangle \in \mathbf{Z}.

h) There exists a real number u≠0u\not= 0 such that the series with general term sin(uθnu\theta^n)2^2 converges; the series with general term ⟨uθn⟩\langle u\theta^n\rangle converges.

i) For every n∈Nn\in \mathbf{N}, let cnc_n be an integer such that ∣uθn−cn∣⩽12|u\theta^n-c_n|\leqslant \frac{1}{2}. The formal series g(z)=∑cnzng(z) =\sum c_nz^n is a rational fraction. (Use the criterion of A, IV, p. 85, exercise 1, and Hadamard's inequality, EVT, V, p. 37, cor. 3, to show that the Hankel determinants which arise tend to 0; conclude by observing that these determinants are integers.)

j) There exist polynomials with integer coefficients f1f_1 and f2f_2 such that g=f1/f2g=f_1/f_2 and f2(0)=1f_2(0) = 1.

k) The number θ\theta is a Pisot number ("Salem's theorem"). (Observe that f2(λ)=0f_2(\lambda ) = 0 and that the other roots of f2f_2 have modulus >1>1.)

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Machine translation of the English, by gpt-5.4. Not checked by a person.