Bourbaki

Exercise 67, § 1

Tag 02M7, permanent. Cite it as [Bourbaki, Tag 02M7].

Spectral Theories, II, p. 301

Bourbaki marks this one as harder than the rest.

Let k⩾2k\geqslant 2 and ℓ>k\ell > k be natural numbers. For every integer N⩾1N\geqslant 1, let rk,ℓ(N)r_{k,\ell}(N) denote the number of families (n1,...,nℓ)∈Nℓ(n_1, . . . , n_{\ell})\in \mathbf{N}^{\ell} such that

n1k+⋯+nℓk=N n^k_1+\cdots +n^k_{\ell}= N

The object of this exercise is to prove that, if ℓ\ell is sufficiently large as a function of kk, then rk,ℓ(N)⩾1r_{k,\ell}(N)\geqslant 1 ("Waring's problem") for every N⩾1N\geqslant 1.

Let e:T→C∗e:\mathbf{T}\rightarrow \mathbf{C}^* denote the character defined by passing to the quotient from the character x↦e2iπxx\mapsto e^{2i\pi x} of R\mathbf{R}.

Let P⩾1P\geqslant 1 be an integer. Let SPS_P denote the function on T\mathbf{T} such that

SP(x)=∑n=1Pe(xnk) S_P(x) =\sum_{n=1}^Pe(xn^k)

Let dxdx denote the normalized Haar measure on T\mathbf{T}.

a) If P>N1/kP>N^{1/k}, then one has

rk,ℓ(N)=∫TSP(x)ℓe(−Nx)dx r_{k,\ell}(N) =\int_{\mathbf{T}}S_P(x)^{\ell}e(-Nx)dx

b) Let δ\delta be a real number such that 0<δ<1/30< \delta <1/3 and let P=[N1/k]P = [N^{1/k}]. Suppose that N is sufficiently large, so that P⩾1P\geqslant 1. Let aa and qq be relatively prime integers such that 1⩽q⩽Pδ1\leqslant q\leqslant P^{\delta}. Let Ma,qM_{a,q} denote the image in T\mathbf{T} of the open interval

]aq−1Pk−δ,aq+1Pk−δ[. \left]\frac{a}{q}-\frac{1}{P^{k-\delta}},\frac{a}{q}+\frac{1}{P^{k-\delta}}\right[.

For x∈Ma,qx\in M_{a,q}, one has

∑n=1Pe2iπxnk=1qS(a;q)I(x−aq)+O(P2δ) \sum_{n=1}^{P}e^{2i\pi xn^k}=\frac{1}{q}S(a;q)I\left(x-\frac{a}{q}\right)+O(P^{2\delta})

as N→+∞N\rightarrow+\infty, where

S(a;q)=∑x=1qe(axkq),I(y)=∫0Pe(ytk) dt. S(a;q)=\sum_{x=1}^{q}e\left(\frac{ax^k}{q}\right),\qquad I(y)=\int_0^{P}e(yt^k)\,dt.

c) Let M denote the union of the sets Ma,qM_{a,q} when qq runs through the set of integers such that 1⩽q⩽Pδ1\leqslant q\leqslant P^{\delta} and aa the set of integers prime to qq such that 1⩽a<q1\leqslant a < q. If δ<1/5\delta <1/5, then there exists a real number δ′>0\delta '>0 such that

∫MSP(x)ℓe(−Nx)dx=Pℓ−kS(Pδ,N)J(Pδ)+O(Pℓ−k−δ′) \int_MS_P(x)^{\ell}e(-Nx)dx= P^{\ell-k}\mathfrak{S}(P^{\delta},N)J(P^{\delta}) + O(P^{\ell-k-\delta'})

as N→+∞N\rightarrow +\infty, where one puts, for Q⩾1Q\geqslant 1

qq

1 ℓaN\ell aN S(Q,N)=∑∑S(a;q)e−\mathfrak{S}(Q,N) =\sum\sum S(a;q)e-

qq qq
1⩽q⩽Qa=11\leqslant q\leqslant Qa=1
(a,q)=1 (a,q)=1
∫Q∫1ℓ \int Q\int 1\ell

J(Q) = e(ytk)dte(−y)dye(yt^k)dte(-y)dy.

−Q-Q 0

d) One has

Γ(1+1/k)ℓ−(ℓ/k−1) \Gamma (1 + 1/k)^{\ell}-_{(\ell /k-1)}

J(Q) = + O(Q )

Γ(ℓ/k) \Gamma (\ell /k)

as Q→+∞Q\rightarrow +\infty. (First prove that

1∫−1+1/k−(ℓ/k−1) 1\int-1+1/k-(\ell /k-1)

J(Q) = (y1⋯yℓ−1(1−y1−⋯−yℓ−1))dy+O(Q(y_1\cdots y_{\ell-1}(1-y_1- \cdots -y_{\ell-1}))dy+ O(Q )

kXℓℓ k^{\ell}_{X_{\ell}}

where

Xℓ={(y1,...,yℓ−1)∈(R+∗)ℓ−1∣y1+⋯+yℓ−1<1} X_{\ell}=\{(y_1, . . . , y_{\ell-1})\in (\mathbf{R}^*_+)^{\ell-1}|y_1+\cdots +y_{\ell-1}<1\}

then evaluate this integral; cf. FVR VII, p. 8, Prop. 4.)

e) Suppose that ℓ>δ−1k2k\ell > \delta^{-1}k2^k. There exists δ′>0\delta '>0 such that

∫T−M∣SP(x)∣ℓe(−Nx)dx=O(Pℓ−k−δ′) \int_{\mathbf{T}-M}|S_P(x)|^{\ell}e(-Nx)dx= O(P^{\ell-k-\delta'})

when N→+∞N\rightarrow +\infty. (If N is sufficiently large and if x∈Rx\in \mathbf{R} has image in T−\mathbf{T}- M, there exist integers aa and qq relatively prime such that

Pδ⩽q⩽Pk−δ,∣x−a∣⩽12 P^{\delta}\leqslant q\leqslant P^{k-\delta},|x-a|\leqslant 1_2
qq qq

Then use Exercise 66.)

f) For every prime number pp and every integer m⩾1m\geqslant 1, let us put

A(pm)=∑pm(1pmS(a;pm))ℓe(−aNpm) A(p^m) =\sum^{p^m}(\frac{1}{p^m}S(a;p^m))^{\ell}e(-\frac{aN}{p^m})
a=1a=1 (a,q)=1(a,q)=1

and

N(pm)=N(p^m) = Card({(x1,...,xℓ)∈(Z/pmZ)ℓ∣x1k+⋯+xℓk=N\{(x_1, . . . , x_{\ell})\in (\mathbf{Z}/p^m\mathbf{Z})^{\ell}|x^k_1+\cdots +x^k_{\ell}= N mod.pm}. p^m\}). When ℓ>2k\ell >2^k, one has

+∞m+\infty m

1+∑A(pm)=1 +\sum A(p^m) = limm→+∞N(p)pm(ℓ−1)_{m\rightarrow+\infty}\frac{N(p )}{p^{m(\ell-1)}}.

m=1m=1

g) When ℓ>2k\ell >2^k, one has S(Q,N)=S(N)+o(1)\mathfrak{S}(Q,N) =\mathfrak{S}(N) +o(1) when Q→+∞Q\rightarrow +\infty, where

S(N)=∏p(1+∑m⩾1A(pm)) \mathfrak{S}(N) =\prod_p(1 +\sum_{m\geqslant 1}A(p^m))

the product being taken over the prime numbers is absolutely convergent. h) Let pp be a prime number. Let ν⩾0\nu \geqslant 0 be the integer such that k=pνrk=p^{\nu}r where pp does not divide rr. Let us denote by γ\gamma the integer

{ν+1\{\nu + 1 if p⩾3p\geqslant 3

γ= \gamma =

ν+2\nu + 2 otherwise.

If there exist integers (n1,...,nℓ)(n_1, . . . , n_{\ell}) such that pp does not divide all the nin_i and such that

x1k+⋯+xℓk≡0x^k_1+\cdots +x^k_{\ell}\equiv 0 mod.pγ. p^{\gamma},

then

limm→+∞N(pm)pm(ℓ−1)>0_{m\rightarrow+\infty}\frac{N(p^m)}{p^{m(\ell-1)}}>0.

i) There exists ℓ>k\ell > k such that, if N is sufficiently large, then S(N)>0\mathfrak{S}(N)>0. (Use the preceding question and question h) of Exercise 33.)

j) There exists an integer ℓ>k\ell > k such that rk,ℓ(N)⩾1r_{k,\ell}(N)\geqslant 1 for every integer N⩾1N\geqslant 1.

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Machine translation of the English, by gpt-5.4. Not checked by a person.