Bourbaki

Exercise 68, § 1

Tag 02M8, permanent. Cite it as [Bourbaki, Tag 02M8].

Spectral Theories, II, p. 303

We denote additively the group law of G. Let Γ be a discrete subgroup of G such that G/ΓG/\Gamma is compact. Let Λ=Γ⊥\Lambda = \Gamma^{\bot} be the orthogonal of Γ in G^\widehat{G}; since G^/Γ\widehat{G}/\Gamma identifies with Λ, it is a discrete subgroup of G^\widehat{G}, and G^/Λ\widehat{G}/\Lambda is compact (since its dual identifies with Γ).

We suppose that the Haar measure on G is chosen in such a way that the quotient of the dual measure dχd\chi on G^\widehat{G} by the counting measure on Λ is the normalized Haar measure on G^/Λ\widehat{G}/\Lambda (INT, VII, § 2, no2^o2, def. 1).

a) There exists a measurable subset Ω of G^\widehat{G} which meets each class of G modulo Λ at one and only one point; the measure of Ω is equal to 1.

b) For x∈Gx\in G, we put

φ(x)=∫Ωχ(x)dχ \varphi (x) =\int_{\Omega}\chi (x)d\chi

The function φ\varphi is continuous; it satisfies φ(0)=1\varphi (0) = 1 and φ(γ)=0\varphi (\gamma ) = 0 for every γ∈Γ−{0}\gamma \in \Gamma -\{0\}.

c) Exercise prove that φ\varphi belongs to L2(G)L^2(G) and that ∥φ∥2=1\|\varphi \|_2= 1. For every γ∈\gamma \in Γ −{e}-\{e\}, one has

∫Gφ(x)φ(γ−x)‾dx=0 \int_G\varphi (x)\overline{\varphi(\gamma-x)}dx= 0

d) Let f∈L2(G)f\in L^2(G) such that F(f)\mathscr{F}(f) is null almost everywhere outside Ω. Exercise prove that

f=∑γ∈Γf(γ)δγ(φ) f=\sum_{\gamma\in\Gamma}f(\gamma )\boldsymbol{\delta }_{\gamma}(\varphi )

in L2(G)L^2(G), where δγ(φ)(x)=φ(x−γ)\boldsymbol{\delta }_{\gamma}(\varphi )(x) =\varphi (x-\gamma ). Moreover, one has

∫G∣f(x)∣2dx=∑γ∈Γ∣f(γ)∣2 \int_G|f(x)|^2dx=\sum_{\gamma\in\Gamma}|f(\gamma )|^2

e) There exists a unique continuous function on G which coincides almost everywhere with ff. If ff is continuous, then

f=∑γ∈Γf(γ)δγ(φ) f=\sum_{\gamma\in\Gamma}f(\gamma )\boldsymbol{\delta }_{\gamma}(\varphi )

in C(G)\mathscr{C}(G).

f) Specialize to the case where G=RG =\mathbf{R} and Λ=hZ\Lambda =h\mathbf{Z} for a certain h>0h >0 by taking Ω=[−h,h[\Omega = [-h, h[.

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Machine translation of the English, by gpt-5-6. Not checked by a person.