Bourbaki

Remark

Tag 02QZ, permanent. Cite it as [Bourbaki, Tag 02QZ].

Théories spectrales, chapter III, § 2. Exemples d’applications linéaires compactes

In the case p=q=2p=q= 2, it is generally more convenient to express the characterization of the integral operator uku_k by means of the scalar product: it is the unique mapping of L2(X)L^2(X) into L2(Y)L^2(Y) such that

⟨g∣uk(f)⟩=∫X×Yk(x,y)f(x)g(y)‾d(μ⊗ν)(x,y) \langle g|u_k(f)\rangle =\int_{X\times Y}k(x, y)f(x)\overline{g(y)}d(\mu\otimes \nu )(x, y)

for all f∈L2(X)f\in L^2(X) and g∈L2(Y)g\in L^2(Y). Moreover, the adjoint of uku_k is the linear mapping uk∗u_{k^*}, where k∗∈L2(Y×X)k^*\in L^2(Y\times X) satisfies k∗(y,x)=k(x,y)k^*(y, x) =k(x, y) for almost every (y,x)∈Y×X(y, x)\in Y\times X. In fact, for all f∈L2(X)f\in L^2(X) and g∈L2g\in L^2(Y), one has

⟨g∣uk(f)⟩=∫X×Yk(x,y)g(y)‾f(x)d(μ⊗ν)(x,y)=⟨uk∗(g)∣f⟩ \langle g|u_k(f)\rangle =\int_{X\times Y}k(x, y)\overline{g(y)}f(x)d(\mu\otimes \nu )(x, y) =\langle u_{k^*}(g)|f\rangle

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.