Bourbaki

Lemma 5

Tag 02R7, permanent. Cite it as [Bourbaki, Tag 02R7].

Théories spectrales, chapter III, § 2. Exemples d’applications linéaires compactes

Let X0X_0 be the underlying real analytic manifold of X and E0E_0 the complex vector bundle on X0X_0 underlying E.

a) The vector subspace Sω(X;E)\mathscr{S}^{\omega}(X; E) of S0(X0;E0)\mathscr{S}^0(X_0; E_0) is closed, and the injection of Sω(X;E)\mathscr{S}^{\omega}(X; E) into S0(X0;E0)\mathscr{S}^0(X_0; E_0) is continuous and strict ;

b) The canonical injection of Sω(X;E)\mathscr{S}^{\omega}(X; E) into S1(X0;E0)\mathscr{S}^1(X_0; E_0) is continuous.

Suppose first that there exist an integer n⩾0n\geqslant 0 and a Banach space F such that X is an open subset of Cn\mathbf{C}^n and E the trivial vector bundle X×FX\times F. In this case, the topological vector spaces Sω(X;E)\mathscr{S}^{\omega}(X; E), S0(X0;E0)\mathscr{S}^0(X_0; E_0) and S1(X0;E0)\mathscr{S}^1(X_0; E_0) are isomorphic to Cω(X;F),C0(X0;F)\mathscr{C}^{\omega}(X; F),\mathscr{C}^0(X_0; F) and C1(X0;F)\mathscr{C}^1(X_0; F) respectively, and the vector space S0(X0;E0)\mathscr{S}^0(X_0; E_0) is metrizable (TG, X, p. 20, cor. of prop. 1). The lemma then follows from VAR, 3.3.2, p. 28.

Let us pass to the general case. Let F\mathfrak{F} be a filter on Sω(X;E)\mathscr{S}^{\omega}(X; E) which converges in the space S0(X0;E0)\mathscr{S}^0(X_0; E_0) to a limit ff. It is a question of proving that ff belongs to Sω(X;E)\mathscr{S}^{\omega}(X; E) and that the filter F\mathfrak{F} converges to ff in the space S1(X0;E0)\mathscr{S}^1(X_0; E_0). This statement is of a local nature, and therefore follows from the first part of the proof.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.