Bourbaki

Lemma 7

Tag 02XC, permanent. Cite it as [Bourbaki, Tag 02XC].

Théories spectrales, chapter IV, § 1. Opérateurs compacts sur un espace hilbertien

Let λ=(λi)i∈I\lambda = (\lambda_i)_{i\in I} be a family of complex numbers. For each t∈C∗t\in \mathbf{C}^*, let ntn_t be the cardinal of the set of i∈Ii\in I such that λi=t\lambda_i=t. The family (λi)i∈I(\lambda_i)_{i\in I} is summable if and only if ntn_t is finite for each t∈C∗t\in \mathbf{C}^* and the family (ntt)t∈C∗(n_tt)_{t\in\mathbf{C}^*} is summable. In this case, the sums of these two families are equal.

Suppose that the family (λi)i∈I(\lambda_i)_{i\in I} is summable. For each t∈Ct\in \mathbf{C}, let ItI_t be the set of i∈Ii\in I such that λi=t\lambda_i=t. By TG, III, p. 39, Theorem 2, applied to the partition of I by the sets ItI_t, the set ItI_t is finite for each t∈C∗t\in \mathbf{C}^*, and moreover the family (ntt)t∈C∗(n_tt)_{t\in\mathbf{C}^*} is summable, with sum equal to that of the family (λi)i∈I(\lambda_i)_{i\in I}.

Conversely, suppose that ntn_t is finite for each t∈C∗t\in \mathbf{C}^* and that the family (ntt)t∈C∗(n_tt)_{t\in\mathbf{C}^*} is summable. Let J be a finite subset of I and Λ the set of the λi\lambda_i for i∈Ji\in J. We have

∣∑i∈Jλi∣⩽∑t∈Λ−{0}nt∣t∣⩽∑t∈C∗nt∣t∣ |\sum_{i\in J}\lambda_i|\leqslant \sum_{t\in\Lambda-\{0\}}n_t|t|\leqslant \sum_{t\in\mathbf{C}^*}n_t|t|

hence the family (λi)i∈I(\lambda_i)_{i\in I} is summable (TG, VII, p. 17, corollary).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Machine translation of the English, by gpt-5-6-mini, gpt-5-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.