Bourbaki

Proposition 16

Tag 02XM, permanent. Cite it as [Bourbaki, Tag 02XM].

Théories spectrales, chapter IV, § 1. Opérateurs compacts sur un espace hilbertien

Let E1E_1 and F1F_1 be Hilbert spaces. Let uu be in L1(E;F),v\mathscr{L}_1(E; F),v be in L(E1;E)\mathscr{L}(E_1; E) and v2v_2 be in L(F;F1)\mathscr{L}(F; F_1). Then v2uv1∈L1(E1;F1)v_2uv_1\in \mathscr{L}_1(E_1; F_1) and ∥v2uv1∥1⩽∥v2∥∥v1∥∥u∥1\|v_2uv_1\|_1\leqslant \|v_2\| \|v_1\| \|u\|_1.

Let w∈L2(E;F1)w\in \mathscr{L}_2(E; F_1) such that ∥w∥⩽1\|w\|\leqslant 1. One has v2u∈L2(E;F1)v_2u\in \mathscr{L}_2(E; F_1) (EVT, V, p. 52, formula (36)). Since v2∗w∈L2(E;F)(v^*_2w\in \mathscr{L}_2(E; F) (loc. cit.), it follows that

∣⟨w∣v2u⟩∣=∣⟨v2∗w∣u⟩∣⩽∥v2∥∥u∥1 |\langle w|v_2u\rangle |=|\langle v^*_2w|u\rangle |\leqslant \|v_2\| \|u\|_1

(formula (11)), whence v2u∈L1(E;F1)v_2u\in \mathscr{L}_1(E; F_1) and ∥v2u∥1⩽∥v2∥∥u∥1\|v_2u\|_1\leqslant \|v_2\|\|u\|_1 (Prop. 14).

Let v1∈L(E1;E)v_1\in \mathscr{L}(E_1; E); since uv1=(v1∗u∗)∗uv_1= (v^*_1u^*)^*, one has uv1∈L1(E1;F)uv_1\in \mathscr{L}_1(E_1; F) and ∥uv1∥1⩽∥v1∗∥∥u∗∥1=∥v1∥∥u∥1\|uv_1\|_1\leqslant \|v^*_1\| \|u^*\|_1=\|v_1\| \|u\|_1 (Lemma 8).

The proposition follows at once from these inequalities.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Machine translation of the English, by gpt-5-6-mini, gpt-5-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.