Bourbaki

Lemma 1

Tag 03C2, permanent. Cite it as [Bourbaki, Tag 03C2].

Théories spectrales, chapter V, § 3. Fonctions de type positif

Let D be the open unit disk in C\mathbf{C}. There exists a unique holomorphic function ff defined on D such that f(z)2=1−zf(z)^2= 1-z for every z∈Dz\in D and f(0)=1f(0) = 1. One has f∗=ff^*=f.

The radius of convergence of the power series

+∞(1/2)n ^{+\infty}(1/2)_n
∑(−z) \sum(-z)
n n
n=0n=0

is equal to 1 and its sum ff defines a holomorphic function on D (VAR,

√ \surd

R1, p. 27, 3.2.9) taking the value 1 at 0. It satisfies f(x)=1−xf(x) =1-x for every x∈D∩Rx\in D\cap \mathbf{R} (FVR, III, p. 19), hence f(z)2=1−zf(z)^2= 1-z for z∈Dz\in D since the difference f(z)2−(1−z)f(z)^2-(1-z) is a holomorphic function all of whose successive derivatives vanish at 0 (VAR, R1, p. 27, 3.2.5). By definition, one verifies that f∗=ff^*=f.

Let gg be a holomorphic function on D such that g(z)2=1−zg(z)^2= 1-z for every z∈Dz\in D and such that g(0)=1g(0) = 1. The function gg does not vanish and the continuous function f/gf /g on D takes its values in {−1,1}\{-1,1\}; since D is connected and f(0)=gf(0) =g(0), one has f=gf=g.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.