Bourbaki

Theorem 5 (Bochner)

Tag 03CZ, permanent. Cite it as [Bourbaki, Tag 03CZ].

Théories spectrales, chapter V, § 3. Fonctions de type positif

A continuous function φ\varphi on G^\widehat{G} belongs to Pos(G^\widehat{G}) if and only if there exists a bounded positive measure ν\nu on G such that φ=F(ν)\varphi =\mathscr{F}(\nu ).

Let ν∈M1(G)\nu \in \mathscr{M}^1(G) be a positive measure. Its Fourier transform is continuous. For every finite family (xi)i∈I(x_i)_{i\in I} in G^\widehat{G} and every finite family (ti)i∈I(t_i)_{i\in I} of complex numbers, one obtains

∑i∈I∑j∈It‾itjF(ν)(xi−1xj)=∑i∈I∑j∈It‾itj∫Gxix‾jdν \sum_{i\in I}\sum_{j\in I}\overline{t}_it_j\mathscr{F}(\nu )(x^{-1}_ix_j) =\sum_{i\in I}\sum_{j\in I}\overline{t}_it_j\int_Gx_i\overline{x}_jd\nu
=∫G∣∑i∈It‾ixi∣2dν⩾0 =\int_G|\sum_{i\in I}\overline{t}_ix_i|^2d\nu \geqslant 0

since ν\nu is a positive measure. The Fourier transform of ν\nu is therefore a function of positive type on G^\widehat{G} (Th. 1 of V, p. 432, (ii)).

Let us prove the converse. Endow the set Pos⩽1(G^)_{\leqslant 1}(\widehat{G}) with the weak topology, induced as above by the weak topology σ(L∞(G^),L1(G^))\sigma (L^{\infty}(\widehat{G}),L^1(\widehat{G})). The set Pos⩽1(G^)_{\leqslant 1}(\widehat{G}) is compact and convex (Cor. to Prop. 13 of V, p. 448). By Prop. 14 of V, p. 450, Prop. 11 of V, p. 444 and Cor. 7 of V, p. 390, the extreme points of Pos⩽1(G^)_{\leqslant 1}(\widehat{G}) are the zero function and the elements of G^\widehat{G}.

Let N\mathscr{N} be the set of bounded positive measures of mass ⩽1\leqslant 1 on G; it is compact in M1(G)\mathscr{M}^1(G) endowed with the weak topology (EVT, III, p. 17, Cor. 3). By Lemma 9 and the first part of the proof, the Fourier transform on G defines, by passing to subspaces, a continuous mapping of N\mathscr{N} into Pos⩽1(G^)_{\leqslant 1}(\widehat{G}); by homogeneity, it is enough to prove that this mapping is surjective. The image F(N)\mathscr{F}(\mathscr{N}) of N\mathscr{N} under the Fourier transform is convex and compact; it contains the zero function and the elements of G^\widehat{G} (in fact, these are of the form evx:χ↦χ(x)_x:\chi \mapsto \chi (x) for an element xx of G by Th. 2 of II, p. 220, and one has evx=F(εx−1)_x=\mathscr{F}(\varepsilon_{x^{-1}})). The set F(N)\mathscr{F}(\mathscr{N}) therefore contains the extreme points of Pos⩽1_{\leqslant 1}(G), whence F(N)=\mathscr{F}(\mathscr{N}) = Pos⩽1(G)_{\leqslant 1}(G) by the Krein-Milman theorem (EVT, II, p. 59, Th. 1). This concludes the proof.

When G=RkG =\mathbf{R}^k for an integer k∈Nk\in \mathbf{N}, this theorem corresponds to Prop. 11 of INT, IX, p. 94, § 6, no12^o12.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.