Bourbaki

Exercise 5, § 3

Tag 03D4, permanent. Cite it as [Bourbaki, Tag 03D4].

Spectral Theories, V, p. 494

Let X be a separated topological space. A continuous function f:X×X→Rf: X\times X\rightarrow \mathbf{R} is said to be conditionally of negative type if it satisfies the conditions

(i) For every x∈Xx\in X, one has f(x,x)=0f(x, x) = 0;

(ii) For all xx and yy in X, one has f(x,y)=f(y,x)f(x, y) =f(y, x);

(iii) For every integer n∈Nn\in \mathbf{N}, every family (xi)0⩽i⩽n(x_i)_{0\leqslant i\leqslant n} of elements of X and every family (ti)0⩽i⩽n(t_i)_{0\leqslant i\leqslant n} of real numbers such that

∑i=1nti=0 \sum_{i=1}^nt_i= 0

one has

∑i=0n∑j=0ntitjf(xi,xj)⩽0 \sum_{i=0}^n\sum_{j=0}^nt_it_jf(x_i, x_j)\leqslant 0

Denote by Noy−(X)_-(X) the set of functions conditionally of negative type on X×XX\times X.

a) Let E be a real Hilbert space and φ:X→E\varphi : X\rightarrow E a continuous mapping. The function f(x,y)=∥φ(x)−φ(y)∥2f(x, y) =\|\varphi (x)-\varphi (y)\|^2 is conditionally of negative type. b) Let f∈f\in Noy−(X)_-(X) and x0∈Xx_0\in X. There exist a real Hilbert space E and a continuous mapping φ:X→E\varphi : X\rightarrow E such that

a) For every (x,y)∈X×X(x, y)\in X\times X, one has f(x,y)=∥φ(x)−φ(y)∥2f(x, y) =\|\varphi (x)-\varphi (y)\|^2;

b) The family (φ(x)−φ(x0))x∈X(\varphi (x)-\varphi (x_0))_{x\in X} is total in E.

One says that (E,φ)(E, \varphi ) is a cyclic Hilbertian representation of ff.

c) Let f∈f\in Noy−(X)_-(X) and x0∈Xx_0\in X. Let (E,φ)(E, \varphi ) and (E′,φ′)(E', \varphi ') be cyclic Hilbertian representations of ff. There exists a unique affine isometry u:E→E′u: E\rightarrow E' such that φ′=u∘φ\varphi '=u\circ \varphi.

d) The set Noy−(X)_-(X) is a convex cone in C(X×X;R)\mathscr{C}(X\times X;\mathbf{R}). For every universally positive kernel g∈g\in Noy+(X)_+(X) such that gg is real-valued, the mapping f(x,y)=g(x,x)−g(x,y)f(x, y) =g(x, x)-g(x, y) belongs to Noy−(X)_-(X).

e) Let F\mathfrak{F} be a filter on Noy−(X)_-(X) which converges simply to f:X×X→Rf: X\times X\rightarrow \mathbf{R}. If ff is continuous, then f∈f\in Noy−(X)_-(X).

f ) Let f:X×X→Rf: X\times X\rightarrow \mathbf{R} be a continuous function satisfying conditions (i) and (ii) above. Let x0∈Xx_0\in X. Let g:X×X→Rg: X\times X\rightarrow \mathbf{R} be such that g(x,y)=f(x,x0)+g(x, y) =f(x, x_0) + f(y,x0)−f(x,y)f(y, x_0)-f(x, y). Then f∈f\in Noy−(X)_-(X) if and only if g∈g\in Noy+(X)_+(X).

g) Suppose X nonempty. Let f:X×X→Rf: X\times X\rightarrow \mathbf{R} be a continuous function satisfying conditions (i) and (ii) above. Then f∈f\in Noy−(X)_-(X) if and only if one has exp(−tf-tf)∈\in Noy+(X)_+(X) for all t∈R+t\in \mathbf{R}_+ ("Schoenberg's theorem"). (To prove that exp(−f-f) is of positive type when f∈f\in Noy−_-(X), fix x0∈Xx_0\in X; prove that

g(x,y)=g(x, y) = exp(f(x,x0)+f(y,x0)−f(x,y)f(x, x_0) +f(y, x_0)-f(x, y))

and

h(x,y)=h(x, y) = exp(−f(x,x0)-f(x, x_0)) exp(−f(y,x0)-f(y, x_0))

belong to Noy+(X).)_+(X).)

If G is a topological group, a function φ∈C(G)\varphi \in \mathscr{C}(G) is said to be of negative type if the function ff on G×GG\times G defined by f(g,h)=φ(h−1g)f(g, h) =\varphi (h^{-1}g) is a conditionally negative type kernel.

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Machine translation of the English, by gpt-5.4. Not checked by a person.