Bourbaki

Exercise 3, § 3

Tag 03L5, permanent. Cite it as [Bourbaki, Tag 03L5].

Theory of Sets, III, 229

Bourbaki marks this one as harder than the rest.

Let (aι)ι∈I(\mathfrak{a}_\iota)_{\iota \in \mathrm{I}} and (bι)ι∈I(\mathfrak{b}_\iota)_{\iota \in \mathrm{I}} be two families of cardinals such that bι⩾2\mathfrak{b}_\iota \geqslant 2 for each ι∈I\iota \in \mathrm{I}.

(a) Show that. if aι⩽bι\mathfrak{a}_\iota \leqslant \mathfrak{b}_\iota for each ι∈I\iota \in \mathrm{I}, then

∑ι∈Iaι⩽Pι∈Ibι.\sum_{\iota \in \mathrm{I}} \mathfrak{a}_\iota \leqslant \mathbf{P}_{\iota \in \mathrm{I}} \mathfrak{b}_\iota.

(b) Show that, if aι<bι\mathfrak{a}_\iota < \mathfrak{b}_\iota for each ι∈I\iota \in \mathrm{I}, then

∑ι∈Iaι<Pι∈Ibι.\sum_{\iota \in \mathrm{I}} \mathfrak{a}_\iota < \mathbf{P}_{\iota \in \mathrm{I}} \mathfrak{b}_\iota.

(Note that a product ∏ι∈IEι\prod_{\iota \in \mathrm{I}} \mathrm{E}_\iota cannot be the union of a family (Aι)ι∈I(\mathrm{A}_\iota)_{\iota \in \mathrm{I}} such that Card (Aι)<Card (Eι)\mathrm{Card}\,(\mathrm{A}_\iota) < \mathrm{Card}\,(\mathrm{E}_\iota) for all ι∈I\iota \in \mathrm{I}, by observing that Card (prι(Aι))<Card (Eι).\mathrm{Card}\,(\mathrm{pr}_\iota(\mathrm{A}_\iota)) < \mathrm{Card}\,(\mathrm{E}_\iota).)

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Transcribed from the printed volume. Not translated.