Bourbaki marks this one as harder than the rest.
Let (aι)ι∈I and (bι)ι∈I be two families of cardinals such that bι⩾2 for each ι∈I.
(a) Show that. if aι⩽bι for each ι∈I, then
ι∈I∑aι⩽Pι∈Ibι.
(b) Show that, if aι<bι for each ι∈I, then
ι∈I∑aι<Pι∈Ibι.
(Note that a product ∏ι∈IEι cannot be the union of a family (Aι)ι∈I such that Card(Aι)<Card(Eι) for all ι∈I, by observing that Card(prι(Aι))<Card(Eι).)
Nothing.