Bourbaki

Exercise 22, § 6

Tag 03O2, permanent. Cite it as [Bourbaki, Tag 03O2].

Theory of Sets, III, 246

Bourbaki marks this one as harder than the rest.

A cardinal ℵα\aleph_\alpha is said to be inaccessible if the ordinal ωα\omega_\alpha is inaccessible (Exercise 16 (b)). We have then ωα=α\omega_\alpha=\alpha if ωα≠ω0\omega_\alpha\neq\omega_0. A cardinal α\alpha is said to be strongly inaccessible if it is inaccessible and dominant (Exercise 21).

(a) The generalized continuum hypothesis implies that every inaccessible cardinal is strongly inaccessible.

(b) For a cardinal a⩾3\mathfrak{a} \geqslant 3 to be strongly inaccessible it is necessary and sufficient that, for each family (aι)ι∈I(\mathfrak{a}_\iota)_{\iota \in I} of cardinals such that

Card (I)<aandaι<a\text{Card (I)} < \mathfrak{a} \quad \text{and} \quad \mathfrak{a}_\iota < \mathfrak{a}

for all ι∈I\iota \in I, we should have ∏ι∈Iaι<a\prod_{\iota \in I} \mathfrak{a}_\iota < \mathfrak{a}.

(c) For an infinite cardinal a\mathfrak{a} to be strongly inaccessible it is necessary and sufficient that it should be dominant (Exercise 21) and that it should satisfy one of the following two conditions : (i) ab=a\mathfrak{a}^{\mathfrak{b}} = \mathfrak{a} for every cardinal b\mathfrak{b} such that 0<b<a0 < \mathfrak{b} < \mathfrak{a}; (ii) ab=a.2b\mathfrak{a}^{\mathfrak{b}} = \mathfrak{a}.2^{\mathfrak{b}} for every cardinal b>0\mathfrak{b} > 0. (Use Exercises 20 and 21.)

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