Bourbaki

Lemma 5

Tag 042K, permanent. Cite it as [Bourbaki, Tag 042K].

Commutative Algebra, chapter I, § 2. Flat modules

Let (Mi)i∈I(M_i)_{i \in I} be a family of left AA-modules, M=⨁i∈IMiM = \bigoplus_{i \in I} M_i, their direct sum and EE a right AA-module. If, for all i∈Ii \in I, EE is flat for MiM_i, then EE is flat for MM.

(a) Suppose first that I={1,2}I = \{1, 2\}, and let M′M' be a submodule of M=M1⊕M2M = M_1 \oplus M_2, MM, and MM, being canonically identified with submodules of MM. Denote by M1′M'_1 the intersection M′∩M1M' \cap M_1, and by M2′M'_2 the image of M′M' in M2M_2 under the canonical projection pp of MM onto M2M_2. We have a diagram

0⟶M1′→i′M′→p′M2′⟶0↓v1↓v↓v20⟶M1→iM→pM2⟶0 \begin{array}{ccccccccc} 0 & \longrightarrow & M'_1 & \xrightarrow{i'} & M' & \xrightarrow{p'} & M'_2 & \longrightarrow & 0 \\ & & \downarrow v_1 & & \downarrow v & & \downarrow v_2 & & \\ 0 & \longrightarrow & M_1 & \xrightarrow{i} & M & \xrightarrow{p} & M_2 & \longrightarrow & 0 \end{array}

where v1,v,v2,i,i′v_1, v, v_2, i, i' are the canonical injections and p′p' is the mapping with the same graph as the restriction of pp to M′M', which is surjective. It is immediately verified that this diagram is commutative and that its rows are exact. With T(Q)T(Q) and T(v)T(v) used in the same sense as in the proof of Lemma 4, we have a commutative diagram

T(M1′)→T(i′)T(M′)→T(p′)T(M2′)↓T(v1)↓T(v)↓T(v2)T(M1)→T(i)T(M)→T(p)T(M2) \begin{array}{ccccccccc} T(M'_1) & \xrightarrow{T(i')} & T(M') & \xrightarrow{T(p')} & T(M'_2) \\ \downarrow T(v_1) & & \downarrow T(v) & & \downarrow T(v_2) \\ T(M_1) & \xrightarrow{T(i)} & T(M) & \xrightarrow{T(p)} & T(M_2) \end{array}

By Lemma 1 of no. 1 the two rows of this diagram are exact; as E is flat for M1M_1 and MnM_n, T(v1)T(v_1) and T(v2)T(v_2) are injective; moreover, by Lemma 2 of no. 1, T(i)T(i) is injective. Corollary 2 to Proposition 2 of § 1, no. 4 then shows that T(v)T(v) is injective and consequently E is M-flat.

(b) If I is a finite set with n elements, the lemma follows by induction on n using (a).

(c) In the general case let M′M' be a finitely generated submodule of M. Then there exists a finite subset J of the indexing set I such that M′M' is contained in the direct sum MJ=⨁i∈JMiM_J = \bigoplus_{i \in J} M_i. By (b) E is flat for MJM_J; the canonical homomorphism E⊗AM′→E⊗AME \otimes_A M' \to E \otimes_A M, is therefore injective. On the other hand, as MJM_J is a direct factor of M, the canonical homomorphism E⊗AMJ→E⊗AME \otimes_A M_J \to E \otimes_A M is injective (no. 1, Lemma 2). Taking the composition, it follows that E⊗AM,→E⊗AME \otimes_A M, \to E \otimes_A M is injective and E is flat for M by Lemma 3.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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