Bourbaki

Proposition 6

Tag 0457, permanent. Cite it as [Bourbaki, Tag 0457].

Commutative Algebra, chapter II, § 1. Prime ideals

Let (ai)i∈I(a_i)_{i \in I} be a non-empty finite family of ideals of a ring AA which are relatively prime in pairs; let aa be the intersection of the aia_i. For every AA-module MM, the canonical mapping M→∏i∈I(M/aiM)M \to \prod_{i \in I} (M/a_i M) is surjective and its kernel is aMaM.

Clearly the canonical mapping of MM to ∏i∈I(M/aiM)\prod_{i \in I} (M/a_i M) is zero on aMaM; then, by taking quotients, it defines a homomorphism A:M/aM→∏i∈I(M/aiM)A : M/aM \to \prod_{i \in I} (M/a_i M). On the other hand, by Proposition 5, the canonical homomorphism

ψ:A/a→∏i∈I(A/ai) \psi : A/a \to \prod_{i \in I} (A/a_i)
is bijective. Then so is 1M⊗ψ:M⊗(A/a)→M⊗∏i∈I(A/ai)1_M \otimes \psi : M \otimes (A/a) \to M \otimes \prod_{i \in I} (A/a_i). Now M⊗(A/a)M \otimes (A/a) is identified with M/aMM/aM and M⊗∏i∈I(A/ai)M \otimes \prod_{i \in I} (A/a_i) with ∏i∈IM⊗(A/ai)\prod_{i \in I} M \otimes (A/a_i), which is itself identified with ∏i∈I(M/aiM)\prod_{i \in I} (M/a_i M). It is immediately verified that the above identifications transforms 1M⊗ψ1_M \otimes \psi into λ\lambda, whence the proposition.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Transcribed from the printed volume. Not translated.