the continuous mapping associated with ϕ (Proposition 13). For every A-module M,
Supp(M(B))⊂aϕ(Supp(M));if also M is finitely generated, then
Supp(M(B))=aϕ−1(Supp(M)).
Let q be a prime ideal of B and p=ϕ−1(q). Suppose that q belongs to Supp(M(B)); then M(B)⊗BBq=(M⊗AB)⊗BBq=M⊗ABq=(M⊗AAp)⊗ABq, since the homomorphism A→B→Bq factors into A→Ap→Bq (§ 2, no. 1, Proposition 2); the hypothesis M(B)⊗BBq=0 implies therefore M⊗AAq=0, whence the first assertion. As the homomorphism ϕq:Ap→Bq is local, the second assertion follows from the following lemma:
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.