Bourbaki

Proposition 4

Tag 04RJ, permanent. Cite it as [Bourbaki, Tag 04RJ].

Commutative Algebra, chapter V, § 3. Finitely generated algebras over a field

Let AA be a principal ideal domain and (pλ)λ∈L(\mathbf{p}_\lambda)_{\lambda \in L} a representative system of extremal elements of AA (Algebra*, Chapter VII, § 1, no. 3, Definition 2). For AA to be a Jacobson ring, it is necessary and sufficient that LL be infinite.*

The maximal ideals of AA are the ApλA\mathbf{p}_\lambda (loc. cit., no. 2, Proposition 2). If LL is finite, their intersection is the ideal AxAx, where x=∏λ∈Lpλx = \prod_{\lambda \in L} \mathbf{p}_\lambda (ibid.) and hence different from (0)(0); on the other hand, if LL is infinite, the intersection of the ApλA\mathbf{p}_\lambda is (0)(0), every element ≠0\neq 0 of AA being divisible by only a finite number of extremal elements (loc. cit., no. 3, Theorem 2). The proposition then follows from the fact that (0)(0) is the only prime ideal which is not maximal in AA (Algebra, Chapter VI, § 1, no. 13, Proposition 14 (DIV)).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.