Proposition 4
Tag 04T7, permanent. Cite it as [Bourbaki, Tag 04T7].
Commutative Algebra, chapter VI, § 3. Valuations
Let be an integral domain, its field of fractions, and a valuation on . Then there exists a unique valuation on which extends and is the subgroup of generated by .
By Theorem 2 of Algebra, Chapter I, § 2, no. 7, there exists a unique homomorphism from to which extends and is generated by . It remains to prove that satisfies axiom (VL). Then let be such that ; there exists such that and , whence . Since the restriction of to satisfies (VL),
Eliminating from both sides, we obtain
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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