Example (6)
Tag 04TF, permanent. Cite it as [Bourbaki, Tag 04TF].
Commutative Algebra, chapter VI, § 3. Valuations
Let Γ be a totally ordered group and k a field. Let Γ_+ be the monoid of positive elements of Γ and C the algebra of Γ_+ over k. By definition, C has a basis (x_\alpha)_{\alpha \in \Gamma_-} over k whose multiplication table is x_\alpha x_\beta = x_{\alpha + \beta}. If is a non-zero element of C, we write and ; it is immediately verified that the mapping of to satisfies conditions (VL_I) and (VL_{II}) of no. 1 and that is an integral domain. Let be the field of fractions of and the valuation on which extends (Proposition 4, no. 2). As every element of is the difference of two positive elements, admits as order group. Let be the ring of and its maximal ideal; we shall show that is the direct sum of and (identified with ), which will prove that the residue field of is isomorphic to . Clearly . On the other hand, denoting by the ideal of generated by the where , every element of valuation 0 in can be written in the form where and ; then
whence and ; this shows our assertion.
If , then and the above construction then provides valuations on which are improper on , whose order group is and whose residue field is . These valuations depend on the order structure chosen on . For example, can be given the lexicographic ordering. Or indeed, for an irrational number , may be identified with a subgroup of under the homomorphism (a homomorphism which is injective since is irrational) and given the ordering induced by that on .
Other constructions of valuations using Proposition 4 of no. 2 will be described in § 10.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.