Bourbaki

Proposition 5

Tag 04YZ, permanent. Cite it as [Bourbaki, Tag 04YZ].

Commutative Algebra, chapter VII, § 1. Krull domains

Let AA be a Krull domain, KK its field of fractions and (vP)P∈P(A)(v_P)_{P \in P(A)} the family of its essential valuations. Let (nP)P∈P(A)(n_P)_{P \in P(A)} be a family of rational integers which are zero except for a finite number of indices. Then the set of x∈Kx \in K such that vP(x)≥nPv_P(x) \geq n_P for all P∈P(A)P \in P(A) is the divisorial ideal aa of AA such that div a=∑P∈P(A)nP⋅P\text{div } a = \sum_{P \in P(A)} n_P \cdot P.

Let x∈K∗x \in K^*. In order that x∈ax \in a, it is necessary and sufficient that Ax⊂aAx \subset a, hence that div(x)≥div a\text{div}(x) \geq \text{div } a and hence, by (4), that vP(x)≥nPv_P(x) \geq n_P for all P∈P(A)P \in P(A).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Transcribed from the printed volume. Not translated.