Bourbaki

Proposition 15

Tag 053Z, permanent. Cite it as [Bourbaki, Tag 053Z].

Commutative Algebra, chapter VII, § 4. Modules over integrally closed Noetherian domains

Let M be a finitely generated A-module. There exists a free submodule L of M such that M/L is a torsion module and the element c(χ(M/L))c(\chi(M/L)) of C does not depend on the free submodule L chosen.

We write S=A−{0}S = A - \{0\} and let V=S−1M=M⊗AKV = S^{-1}M = M \otimes_A K; if nn is the rank of V over K, there exist nn elements eie_i (1≤i≤n1 \leq i \leq n) of M whose canonical images in V form a basis of V; these elements are obviously linearly independent in M and hence generate a free submodule L of M such that S−1(M/L)=S−1M/S−1L=0S^{-1}(M/L) = S^{-1}M/S^{-1}L = 0, so that M/L is a torsion module.

Now let L, be another free submodule of M of rank nn. Since S−1L=S−1L1S^{-1}L = S^{-1}L_1, there exists s∈Ss \in S such that sL1⊂LsL_1 \subset L; we may therefore limit ourselves to proving that, if L1⊂L2L_1 \subset L_2 are two free submodules of M of rank nn, then

c(χ(M/L1))=c(χ(M/L2)). c(\chi(M/L_1)) = c(\chi(M/L_2)).

Now, χ(M/L1)=χ(M/L2)+χ(L2/L1)\chi(M/L_1) = \chi(M/L_2) + \chi(L_2/L_1) and it follows from no. 6, Corollary to Proposition 14 that χ(L2/L1)\chi(L_2/L_1) is a principal divisor and therefore

c(χ(L2/L1))=0. c(\chi(L_2/L_1)) = 0.

The element c(χ(M/L))c(\chi(M/L)) will be denoted by −c(M)-c(M) in what follows; we shall say that c(M)c(M) is the divisor class attached to M.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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