Theorem 5 (Schreier)
Tag 059E, permanent. Cite it as [Bourbaki, Tag 059E].
Algebra, chapter I, § 4. Groups and groups with operators
*Given two composition series of a group with operators G, there exist two equivalent composition series , finer respectively than and .
Let and be the two given composition series with respectively and terms; we shall see that the composition series can be formed by inserting subgroups (1 \leq j \leq p - 1) between H_i and H_{i+1} for 0 \leq i \leq n - 1 and the series \Sigma_2' by inserting n - 1 subgroups K_{j,i}' (1 \leq i \leq n - 1) between K_j and K_{j+1} for 0 \leq j \leq p - 1; thus two series of pn + 1 stable subgroups of G will be obtained; by choosing suitably the inserted stable subgroups, we shall show that these series are equivalent composition series.
To this end note that H_i \cap K_j is a stable subgroup of H_i and of K_j, and hence (Theorem 4) H_{i+1}.(H_i \cap K_j) is a stable subgroup of H_i containing H_{i+1} and K_{j+1}.(H_i \cap K_j) is a stable subgroup of K_j containing K_{j+1}. If we write H_{i,j}' = H_{i+1}.(H_i \cap K_j) and K_{j,i}' = K_{j+1}.(H_i \cap K_j), H_{i,j+1}' is a stable subgroup of H_{i,j}' (0 \leq j \leq p - 1) and K_{j,i+1}' is a stable subgroup of K_{j,i}' (0 \leq i \leq n - 1). Moreover H_{i,0}' = H_i, H_{i,p}' = H_{i+1}, K_{j,0}' = K_j and K_{j,p}' = K_{j+1}. To show the theorem, it suffices to show that H_{i,j+1}' (resp. K_{j,i+1}') is a normal stable subgroup of H_{i,j}' (resp. K_{j,i}') and that the quotient groups H_{i,j}'/H_{i,j+1}' and K_{j,i}'/K_{j,i+1}' are isomorphic (0 \leq i \leq n - 1, 0 \leq j \leq p - 1). This follows from the following lemma by taking H = H_i, H' = H_{i+1}, K = K_j, K' = K_{j+1}.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.