Bourbaki

Definition 1

Tag 05B1, permanent. Cite it as [Bourbaki, Tag 05B1].

Algebra, chapter I, § 5. Groups operating on a set

Let M be a monoid, with law written multiplicatively and identity element denoted by e, and E a set. An action α↦fα\alpha \mapsto f_\alpha of M on E is called a left (resp. right) operation of M on E if fe=IdEf_e = \mathrm{Id}_E and fαβ=fα∘fβf_{\alpha \beta} = f_\alpha \circ f_\beta (resp. fαβ=fβ∘fαf_{\alpha \beta} = f_\beta \circ f_\alpha) for all α,β∈M\alpha, \beta \in M.

In other words, a left (resp. right) operation of a monoid M on a set E is a monoid homomorphism of M into the monoid EEE^E (resp. the opposite monoid of EEE^E) with composition of mappings. If the law of action corresponding to the action of M is denoted by left (resp. right) multiplication, the fact that this action is a left (resp. right) operation may be expressed by the formulae

(1)

e.x=x;α.(β.x)=(αβ).xfor α,β∈M and x∈E. e.x = x; \quad \alpha.(\beta.x) = (\alpha \beta).x \quad \text{for } \alpha, \beta \in M \text{ and } x \in E.
(resp. x.e=x;(x.α).β=x.(αβ)for α,β∈M and x∈Ex.e = x; \quad (x.\alpha).\beta = x.(\alpha \beta) \quad \text{for } \alpha, \beta \in M \text{ and } x \in E).

Under these conditions, it is also said that M operates on E on the left (resp. right) and that the corresponding laws of action are laws of left (resp. right) operation of the monoid M on E.

Let M be a monoid; a set E with a left (resp. right) operation of M on E is called a left (resp. right) M-set. The monoid M is said to operate on the left (resp. right) faithfully if the mapping α↦fα\alpha \mapsto f_\alpha of M into EEE^E is injective.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

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Transcribed from the printed edition, 1998, Springer. Not translated.