Bourbaki

Example

Tag 05B2, permanent. Cite it as [Bourbaki, Tag 05B2].

Algebra, chapter I, § 5. Groups operating on a set

(1) Let E be a set; the canonical action of EEE^E on E (§ 3, no. 1, Example 3) is a left operation.

(2) Let M be a monoid. The left (resp. right) action of M on itself derived from the law on M (§ 3, no. 3, Example 7) is a left (resp. right) operation of M on itself. When considering this operation, we say that M operates on itself by left (resp. right) translation.

Let E be a left (resp. right) M-set and M0M^0 the opposite monoid to M. Under the same action, the monoid M0M^0 operates on E on the right (resp. left). The M0M^0-set obtained is called opposite to the M-set E. The definitions and results relating to left M-sets carry over to right M0M^0-sets when passing to the opposite structures.

In the rest of this paragraph, we shall consider, unless otherwise stated, only left M-sets which we shall call simply M-sets. Their law of action will be denoted by left multiplication.

Let E be a set. Let G be a group operating on E. For all α\alpha in G, the element of EEE^E defined by α\alpha is a permutation of E (§\S 2, no. 3, Example 2). Being given an operation of G on E therefore amounts to being given a homomorphism of G into SE\mathfrak{S}_E.

In conformity with §\S 3, no. 3, we make the following definition:

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

Transcribed from the printed edition, 1998, Springer. Not translated.