Bourbaki

Example

Tag 05D8, permanent. Cite it as [Bourbaki, Tag 05D8].

Algebra, chapter I, § 6. Extensions, solvable groups, nilpotent groups

(1) If G is a non-commutative simple group, then D(G)=GD(G) = G. Therefore every homomorphism of G into a commutative group is trivial.

(2) The derived group of the symmetric group SnS_n is the alternating group AnA_n. For AnA_n is generated by the products of two transpositions; if τ=τx,y\tau = \tau_{x,y} and τ′=τx′,y′\tau' = \tau_{x',y'} are two transpositions, let σ\sigma be a permutation such that σ(x′)=x\sigma(x') = x and σ(y′)=y\sigma(y') = y. Then τ′=σ−1τσ\tau' = \sigma^{-1} \tau \sigma and ττ′=τ−1τ′=τ−1σ−1τσ\tau \tau' = \tau^{-1} \tau' = \tau^{-1} \sigma^{-1} \tau \sigma is a commutator. Hence An⊂D(Sn)A_n \subset D(S_n). As Sn/AnS_n/A_n is commutative, An⊃D(Sn)A_n \supset D(S_n) (Corollary 3).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 1998, Springer. Not translated.