Bourbaki

Proposition 8

Tag 05DE, permanent. Cite it as [Bourbaki, Tag 05DE].

Algebra, chapter I, § 6. Extensions, solvable groups, nilpotent groups

Let GG be a nilpotent group of class ≤n\leq n and let HH be a subgroup of GG. There exists a sequence of subgroups

G=H1⊃H2⊃…⊃Hn+1=H, G = H^1 \supset H^2 \supset \ldots \supset H^{n+1} = H,

such that Hk+1H^{k+1} is normal in HkH^k and Hk/Hk+1H^k/H^{k+1} is commutative for all k≤nk \leq n.

Choose a sequence (Gk)(G^k) of subgroups of GG satisfying the conditions of Proposition 7 (b) for all kk; GkG^k is normal in GG. Write:

Hk=H.Gk. H^k = H.G^k.

It is necessary to verify that Hk+1H^{k+1} is normalized by Hk=H.GkH^k = H.G^k; as it is normalized by HH, it suffices to verify that it is by GkG^k. Now, if s∈Gks \in G^k and h∈Hh \in H,

shs−1=shs−1h−1.h∈(G,Gk).H shs^{-1} = shs^{-1}h^{-1}.h \in (G, G^k).H

and (G,Gk).H(G, G^k).H is contained in Gk+1.H=Hk+1G^{k+1}.H = H^{k+1}; hence s.Hk+1.s−1=Hk+1s.H^{k+1}.s^{-1} = H^{k+1}, which shows that Hk+1H^{k+1} is normal in HkH^k.

Finally, the canonical homomorphism Gk/Gk+1→Hk/Hk+1G^k/G^{k+1} \to H^k/H^{k+1} is obviously surjective; as the first group is commutative, so is the second.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 1998, Springer. Not translated.