Bourbaki

Definition 1

Tag 05JO, permanent. Cite it as [Bourbaki, Tag 05JO].

Algebra, chapter II, § 1. Modules

Given a ring A\mathbf{A}, a left module over A\mathbf{A} (or left A\mathbf{A}-*module*) is a set E\mathbf{E} with an algebraic structure defined by giving:

(1) a commutative group law on E\mathbf{E} (written additively in what follows);

(2) a law of action (α,x)↦α⊤x(\alpha, x) \mapsto \alpha \top x, whose domain of operators is the ring A\mathbf{A} and which satisfies the following axioms:

(MI)α⊤(x+y)=(α⊤x)+(α⊤y) for all α∈A,x∈E,y∈E;(MII)(α+β)⊤x=(α⊤x)+(β⊤x) for all α∈A,β∈A,x∈E;(MIII)α⊤(β⊤x)=(αβ)⊤x for all α∈A,β∈A,x∈E;(MIV)1⊤x=x for all x∈E. \begin{align*} (\mathbf{M_I})\quad & \alpha \top (x + y) = (\alpha \top x) + (\alpha \top y) \text{ for all } \alpha \in \mathbf{A}, x \in \mathbf{E}, y \in \mathbf{E}; \\ (\mathbf{M_{II}})\quad & (\alpha + \beta) \top x = (\alpha \top x) + (\beta \top x) \text{ for all } \alpha \in \mathbf{A}, \beta \in \mathbf{A}, x \in \mathbf{E}; \\ (\mathbf{M_{III}})\quad & \alpha \top (\beta \top x) = (\alpha \beta) \top x \text{ for all } \alpha \in \mathbf{A}, \beta \in \mathbf{A}, x \in \mathbf{E}; \\ (\mathbf{M_{IV}})\quad & 1 \top x = x \text{ for all } x \in \mathbf{E}. \end{align*}

Axiom (MI)(\mathbf{M_I}) means that the external law of a left A\mathbf{A}-module E\mathbf{E} is distributive with respect to addition on E\mathbf{E}; a module is thus a commutative group with operators.

If in Definition 1, axiom (MIII)(\mathbf{M_{III}}) is replaced by

(MIII′)α⊤(β⊤x)=(βα)⊤x for all α∈A,β∈A,x∈E, (\mathbf{M'_{III}})\quad \alpha \top (\beta \top x) = (\beta \alpha) \top x \text{ for all } \alpha \in \mathbf{A}, \beta \in \mathbf{A}, x \in \mathbf{E},

E with the algebraic structure thus defined is a right module over A or a right A-module.

When speaking of A-modules (left or right), the elements of the ring A are often called scalars.

Usually the external law of composition of a left A-module (resp. right A-module) is written multiplicatively, with the operator written on the left (resp. right); condition (M_{III}) is then written α(βx)=(αβ)x\alpha(\beta x) = (\alpha\beta)x, condition (M'_{III}) is written (xβ)α=x(βα)(x\beta)\alpha = x(\beta\alpha).

If A0A^0 denotes the opposite ring to A (I, § 8, no. 3), every right module E over the ring A is a left module over the ring A0A^0. It follows that an exposition can be given of the properties of modules whilst systematically confining attention either to left modules or to right modules; in §§ 1 and 2 we shall in general give this exposition for left modules and when we speak of a module (without specifying which type) we shall mean a left module whose external law will be written multiplicatively. When the ring A is commutative the notions of right module and left module with respect to A are identical.

For all α∈A\alpha \in A, the mapping x↦αxx \mapsto \alpha x of an A-module E into itself is called the homothety of ratio α\alpha of E (I, § 4, no. 2); by (M_I) a homothety is an endomorphism of the commutative group structure (without operators) on E, but not in general of the module structure on E (I, § 4, no. 2; cf. II, § 1, no. 2 and no. 13). Hence α0=0\alpha 0 = 0 and α(−x)=−(αx)\alpha(-x) = -(\alpha x); if α\alpha is an invertible element of A, the homothety x↦αxx \mapsto \alpha x is an automorphism of the commutative group structure (without operators) on E, for the relation y=αxy = \alpha x implies by virtue of (M_IV), x=α−1(αx)=α−1yx = \alpha^{-1}(\alpha x) = \alpha^{-1}y.

Similarly, by virtue of (M_{II}), for all x∈Ex \in E, the mapping α↦αx\alpha \mapsto \alpha x is a homomorphism of the additive group A into the commutative group (without operators) E; hence 0x=00x = 0 and (−α)x=−(αx)(-\alpha)x = -(\alpha x); moreover, by (M_IV), for every integer n∈Zn \in \mathbf{Z}, n.x=(n.1)xn.x = (n.1)x.

When the ring A consists only of the element 0, every A-module E consists only of the element 0, for then 1=01 = 0 in A, whence, for all x∈Ex \in E, x=1.x=0.x=0x = 1.x = 0.x = 0.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 1998, Springer. Not translated.