Bourbaki

Proposition 7

Tag 05KA, permanent. Cite it as [Bourbaki, Tag 05KA].

Algebra, chapter II, § 1. Modules

(i) Let (Ei)i∈I,(Fi)i∈I(E_i)_{i \in I}, (F_i)_{i \in I} be two families of AA*-modules with the same indexing set* II; for every family of linear mappings fi:Ei→Fif_i : E_i \to F_i (i∈Ii \in I), the restriction to ⨁i∈IEi\bigoplus_{i \in I} E_i of the linear mapping (xi)↦(fi(xi))(x_i) \mapsto (f_i(x_i)) is a linear mapping f:⨁i∈IEi→⨁i∈IFif : \bigoplus_{i \in I} E_i \to \bigoplus_{i \in I} F_i denoted by ⨁i∈Ifi\bigoplus_{i \in I} f_i or ⨁ifi\bigoplus_i f_i (where f=fp⊕fp+1⊕⋯⊕fqf = f_p \oplus f_{p+1} \oplus \cdots \oplus f_q if I=[p,q]I = [p, q] is an interval in Z\mathbf{Z}*).*

(ii) Let (Gi)i∈I(G_i)_{i \in I} be a third family of AA*-modules with* II as indexing set and, for all i∈Ii \in I, let gi:Fi→Gig_i : F_i \to G_i be a linear mapping; we write g=⨁igig = \bigoplus_i g_i. For each of the sequences Ei→fiFi→giGiE_i \xrightarrow{f_i} F_i \xrightarrow{g_i} G_i to be exact, it is necessary and sufficient that the sequence

⨁iEi→f⨁iFi→g⨁iGi \bigoplus_i E_i \xrightarrow{f} \bigoplus_i F_i \xrightarrow{g} \bigoplus_i G_i
be exact.

Obviously, for all (xi)∈⨁iEi(x_i) \in \bigoplus_i E_i, the family (fi(xi))(f_i(x_i)) has finite support, whence (i). On the other hand, to say that an element y=(yi)y = (y_i) of ⨁iFi\bigoplus_i F_i belongs to Ker(g)\mathrm{Ker}(g) means that yi∈Ker(gi)y_i \in \mathrm{Ker}(g_i) for all i∈Ii \in I (no. 5, Proposition 5); similarly, if yi∈Im(fi)y_i \in \mathrm{Im}(f_i) for all i∈Ii \in I, there exists for each i∈Ii \in I an xi∈Eix_i \in E_i such that yi=fi(xi)y_i = f_i(x_i) and when yi=0y_i = 0, it may be supposed that xi=0x_i = 0; hence y∈Im(f)y \in \mathrm{Im}(f) and the converse is obvious.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 1998, Springer. Not translated.