Bourbaki

Proposition 20

Tag 05LL, permanent. Cite it as [Bourbaki, Tag 05LL].

Algebra, chapter II, § 1. Modules

Every A-module E is isomorphic to a quotient module of a free A-module.

If T is a generating set of E, there exists a surjective linear mapping As(T)→EA_s^{(T)} \to E (Corollary 2 to Proposition 17), and if R is the kernel of this mapping, E is isomorphic to As(T)/RA_s^{(T)}/R.

In particular we may take T=ET = E; then there is a surjective linear mapping As(E)→EA_s^{(E)} \to E, called canonical.

In particular, to say that an A-module E is finitely generated (no. 7) means that it is isomorphic to a quotient of a free A-module with a finite basis or also that there exists an exact sequence of the form

Asn→E→0(n an integer >0). A_s^n \to E \to 0 \quad (n \text{ an integer } > 0).

Note that if A≠{0}A \neq \{0\} every basis of a finitely generated free module E is necessarily finite, for if S is a finite generating system and B a basis of E, each element of S is a linear combination of a finite number of elements of B and if B' is the set of all the elements of B which figure thus in the expression for the elements of S, B' is finite and every x∈Ex \in E is a linear combination of elements of B', hence B′=BB' = B.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 1998, Springer. Not translated.