Bourbaki

Definition 11

Tag 05LO, permanent. Cite it as [Bourbaki, Tag 05LO].

Algebra, chapter II, § 1. Modules

The annihilator of a subset S of an A-module E is the set of elements α∈A\alpha \in A such that αx=0\alpha x = 0 for all x∈Sx \in S.

The annihilator of S is usually denoted by Ann(S); for a subset S consisting of a single element x, we write Ann(x) instead of Ann(\{x\}) and call Ann(x) the annihilator of x.

The relation αx=0\alpha x = 0 may also be expressed by saying that x is annihilated by α\alpha.

It is immediate that the annihilator of an arbitrary subset S of E is a left ideal of A; for it to be equal to A, it is necessary and sufficient (by virtue of (M_IV)) that S={0}S = \{0\}. If two subsets S, T of E are such that S⊂TS \subset T, the annihilator of T is contained in the annihilator of S. If (Si)i∈I(S_i)_{i \in I} is an arbitrary family of subsets of E, the annihilator of the union ⋃iSi\bigcup_i S_i is the intersection of the annihilators of the SiS_i. In particular, the annihilator of a subset S of E is the intersection of the annihilators of the elements of S. To say that an element of E is free is equivalent to saying that its annihilator is {0}\{0\}. For all x∈Ex \in E and all α∈A\alpha \in A, the annihilator of αx\alpha x is the set of β∈A\beta \in A such that βα∈Ann(x)\beta \alpha \in \mathrm{Ann}(x).

The annihilator of a submodule M of E is a two-sided ideal of A; for, if αx=0\alpha x = 0 for all x∈Mx \in M, then also α(βx)=0\alpha (\beta x) = 0 for all x∈Mx \in M and all β∈A\beta \in A, hence αβ\alpha \beta belongs to the annihilator of M for all β∈A\beta \in A. In particular, the annihilator of E is a two-sided ideal of A.

For all α∈A\alpha \in A, let hαh_\alpha be the homothety x↦αxx \mapsto \alpha x; it is known that the mapping α↦hα\alpha \mapsto h_\alpha of A into the endomorphism ring E=HomZ(E,E)\mathscr{E} = \mathrm{Hom}_\mathbf{Z}(E, E) of the commutative group (without operators) E, is a ring homomorphism (§ 2, no. 5). The inverse image of 0 under this homomorphism is the annihilator aa of E; the image of A under the homomorphism α↦hα\alpha \mapsto h_\alpha is therefore isomorphic to the quotient ring A/aA/a. The module E is called faithful if its annihilator aa reduces to 0.

Let E be any A-module, aa a two-sided ideal of A contained in Ann(E) and let α˙\dot{\alpha} be an element of the quotient ring A/aA/a; for all x∈Ex \in E, the element αx\alpha x is the same for all the α∈A\alpha \in A belonging to the class α˙\dot{\alpha} mod. aa; if this element is denoted by α˙x\dot{\alpha} x, it is immediately seen that the mapping (α, x) ↦ αx defines (with addition on E) an (A/α)-module structure on E. When α = Ann(E), the (A/α)-module E thus defined is faithful; we shall say that it is the faithful module associated with the A-module E. Observe that every submodule of an A-module E is also a submodule of the associated faithful module and conversely.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 1998, Springer. Not translated.