Example
Tag 05M0, permanent. Cite it as [Bourbaki, Tag 05M0].
Algebra, chapter II, § 1. Modules
It has been seen (no. 1) that a homothety on an -module is not necessarily a linear mapping. But if is invertible, is a semi-linear mapping (which is moreover bijective) relative to the inner automorphism of , for .
Let C be a third ring, a homomorphism and G a C-module. If is a semi-linear mapping relative to , the composition is a semi-linear mapping of G into E relative to the homomorphism . If is an isomorphism and is a bijective semi-linear mapping relative to , the inverse mapping is a semi-linear mapping relative to the inverse isomorphism of .
It is thus seen that, for the species of structure defined by giving on an ordered pair (A, E) of sets a ring structure on A and a left A-module structure on E, the dimorphisms can be taken as morphisms (Set Theory, IV, § 2, no. 1); we shall always assume in what follows that this choice of morphisms has been made.
Remark (3). Let be two rings, their product and let in A, so that and are canonically identified with the two-sided ideals and of A. For every A-module E, and are sub-A-modules of E, annihilated respectively by and , so that, canonically identifying with and with , (resp. ) is given an -module (resp. -module) structure. Moreover, E is the direct sum of and , for every can be written as and the relation implies . Conversely, for every ordered pair consisting of an -module and an -module , let be the A-module , the A-module , and being the projections of A onto and respectively; then in the A-module . The study of A-modules is thus reduced to that of -modules and that of -modules. In particular, every submodule M of E is of the form , where and .
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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