Bourbaki

Corollary

Tag 05QF, permanent. Cite it as [Bourbaki, Tag 05QF].

Algebra, chapter II, § 5. Extension of the ring of scalars

Let E, E' be two left A-modules; for every A-linear mapping u:E→E′u : E \to E', v=lB⊗uv = l_B \otimes u is the unique B-linear mapping which renders commutative the diagram

E→ϕEE(B)∣∣u↓v↓E′→ϕE′E(B)′ \begin{array}{ccc} E & \xrightarrow{\phi_E} & E_{(B)} \\ | & & | \\ u \downarrow & & v \downarrow \\ E' & \xrightarrow{\phi_{E'}} & E'_{(B)} \end{array}

where ϕE\phi_E and ϕE′\phi_{E'} are the canonical mappings.

It suffices to apply Proposition 1 to the A-homomorphism ϕE′∘u:E→E(B)′\phi_{E'} \circ u : E \to E'_{(B)}.

The mapping vv defined in the above corollary is denoted by ρ∗(u)\rho^*(u) or u(B)u_{(B)}.

If E′′E'' is a third left A-module and v:E′→E′′v : E' \to E'' an A-linear mapping, it is immediate that

(v∘u)(B)=v(B)∘u(B). (v \circ u)_{(B)} = v_{(B)} \circ u_{(B)}.

Extending the ring of operators of a module is a transitive operation; to be precise:

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 1998, Springer. Not translated.