Proposition 1
Tag 05QD, permanent. Cite it as [Bourbaki, Tag 05QD].
Algebra, chapter II, § 5. Extension of the ring of scalars
For every left -module , the mapping of into the -module is -linear and the set generates the -module . Further, for every left -module and every -linear mapping of into the -module , there exists one and only one -linear mapping of into such that for all .
can be considered as a -bimodule by means of ; then there is a canonical -module isomorphism
(1)
as has been seen in , no. 1, Proposition 1. But the left -module is canonically identified with : for, by definition (, no. 14), there corresponds to an element the homomorphism such that ; for all , there thus corresponds to the homomorphism of into , which is just for the left -module structure on (, no. 14). Using this identification, we obtain therefore a canonical -module isomorphism, the inverse of (1)
(2)
and it follows immediately from the definitions that if then for all . In particular, the mapping is just (3)
Proposition 1 is therefore proved. The mapping is called canonical.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Cited by
- § 5. Extension of the ring of scalars
- Corollary, § 5
- Remark, § 5
- Proposition 1, § 1
- Proposition 20, § 10
Cites
Nothing.