Bourbaki

Proposition 2

Tag 05Y6, permanent. Cite it as [Bourbaki, Tag 05Y6].

Algebra, chapter II, § 11. Graded modules and rings

Let A be a graded ring of type Δ\Delta, M a graded A-module of type Δ\Delta, (Mλ)(M_\lambda) its graduation and N a sub-A-module of M. The following properties are equivalent:

(a) NN is the sum of the family (N∩Mλ)λ∈Δ(N \cap M_\lambda)_{\lambda \in \Delta}. (b) The homogeneous components of every element of N belong to N. (c) NN is generated by homogeneous elements.

Every element of N can be written uniquely as a sum of elements of the MλM_\lambda and hence it is immediate that (a) and (b) are equivalent and that (a) implies (c). We show that (c) implies (b). Then let (xi)i∈I(x_i)_{i \in I} be a family of homogeneous generators ≠0\neq 0 of N and let δ(i)\delta(i) be the degree of xix_i. Every element of N can be written as ∑iaixi\sum_i a_i x_i with ai∈Aa_i \in A; if ai,λa_{i,\lambda} is the component of aia_i of degree λ\lambda, the conclusion follows from the relation

∑i∈I(∑μ∈Δai,μxi)=∑λ∈Δ(∑μ+δ(i)=λai,μxi). \sum_{i \in I} \left( \sum_{\mu \in \Delta} a_{i,\mu} x_i \right) = \sum_{\lambda \in \Delta} \left( \sum_{\mu + \delta(i) = \lambda} a_{i,\mu} x_i \right).

Remark (1) In the above notation, the relation ∑i∈Iaixi=0\sum_{i \in I} a_i x_i = 0 is therefore equivalent to the system of relations ∑μ+δ(i)=λai,μxi=0\sum_{\mu + \delta(i) = \lambda} a_{i,\mu} x_i = 0. When Δ\Delta is a group, these relations can be written ∑i∈Iai,λ−δ(i)xi=0\sum_{i \in I} a_{i,\lambda - \delta(i)} x_i = 0.

When a submodule N of M has the equivalent properties stated in Proposition 2, clearly the N∩MλN \cap M_\lambda form a graduation compatible with the A-module structure of N, called the graduation induced by that on M; N with this graduation is called a graded submodule of M.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 1998, Springer. Not translated.