Bourbaki

Lemma 1

Tag 05YL, permanent. Cite it as [Bourbaki, Tag 05YL].

Algebra, chapter II, § 11. Graded modules and rings

For a commutative group Δ\Delta to be such that there exists on Δ\Delta a total ordering compatible with the group structure of Δ\Delta, it is necessary and sufficient that Δ\Delta be torsion-free.

If there exists such an order structure on Δ\Delta and if λ>0\lambda > 0, then λ+μ>0\lambda + \mu > 0 for all μ≥0\mu \geq 0 and in particular, by induction on the integer n>0n > 0, n.λ>0n.\lambda > 0, which proves that Δ\Delta is torsion-free (since every element ≠0\neq 0 of Δ\Delta is either >0> 0 or <0< 0). Conversely, if Δ\Delta is torsion-free, Δ\Delta is a sub-Z\mathbf{Z}-module of a vector Q\mathbf{Q}-space (§ 7, no. 10, Corollary 1 to Proposition 26) which may be assumed of the form Q(I)\mathbf{Q}^{(I)}; if II is given a well-ordering (Set Theory, III, § 2, no. 3, Theorem 1) and Q\mathbf{Q} its usual ordering, the set Q(I)\mathbf{Q}^{(I)} with the lexicographical ordering is totally ordered (Set Theory, III, § 2, no. 6); it is immediate that this ordering is compatible with the additive group structure of Q(I)\mathbf{Q}^{(I)}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 1998, Springer. Not translated.