Bourbaki

Proposition 2

Tag 065U, permanent. Cite it as [Bourbaki, Tag 065U].

Algebra, chapter III, § 9. Norms and traces

Let A,A′A, A' be two KK-algebras, MM an AA-module and M′M' an A′A'-module. Suppose that MM and M′M' are free KK-modules of respective dimensions nn and n′n' and consider M⊗KM′M \otimes_K M' as an (A⊗KA′)(A \otimes_K A')-module (§4§ 4, no. 3, Example 2). Then, for a∈Aa \in A and a′∈A′a' \in A',

Tr⁡M⊗M′(a⊗a′)=Tr⁡M(a)Tr⁡M′(a′) \operatorname{Tr}_{M \otimes M'}(a \otimes a') = \operatorname{Tr}_M(a) \operatorname{Tr}_{M'}(a')
(16)

NM⊗M′(a⊗a′)=(NM(a))n′(NM′(a′))n. N_{M \otimes M'}(a \otimes a') = (N_M(a))^{n'} (N_{M'}(a'))^n.
(17)

Formula (16) follows from II, § 4, no. 4, formula (26) and formula (17) from § 8, no. 6, formula (33).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 1998, Springer. Not translated.