Bourbaki

Proposition 19

Tag 0677, permanent. Cite it as [Bourbaki, Tag 0677].

Algebra, chapter III, § 10. Derivations

Let

K→ρK′↓η↓η′A→uA′ \begin{array}{ccc} K & \xrightarrow{\rho} & K' \\ \downarrow \eta & & \downarrow \eta' \\ A & \xrightarrow{u} & A' \end{array}

be a commutative diagram of commutative ring homomorphisms, η\eta (resp. η′\eta') making

A (resp. A′A') into a KK-algebra (resp. K′K'-algebra). There exists one and only one AA-linear mapping v:ΩK(A)→ΩK′(A′)v : \Omega_K(A) \to \Omega_{K'}(A') rendering commutative the diagram

A→uA′dA/K↓dA′/K′↓ΩK(A)→vΩK′(A′) \begin{array}{ccc} A & \xrightarrow{u} & A' \\ d_{A/K} \downarrow & & d_{A'/K'} \downarrow \\ \Omega_K(A) & \xrightarrow{v} & \Omega_{K'}(A') \end{array}

dA′/K′∘ud_{A'/K'} \circ u is a KK-derivation of AA with values in the AA-module ΩK′(A′)\Omega_{K'}(A'); the existence and uniqueness of vv then follow from Proposition 18 of no. 11.

The mapping vv of Proposition 19 will be denoted by Ω(u)\Omega(u); if there is a commutative diagram of commutative ring homomorphisms

K→σK′→σ′K′′η↓η′↓η′′↓A→uA′→u′A′′ \begin{array}{cccccc} K & \xrightarrow{\sigma} & K' & \xrightarrow{\sigma'} & K'' \\ \eta \downarrow & & \eta' \downarrow & & \eta'' \downarrow \\ A & \xrightarrow{u} & A' & \xrightarrow{u'} & A'' \end{array}

it follows immediately from the uniqueness property of Proposition 19 that

Ω(u′∘u)=Ω(u′)∘Ω(u). \Omega(u' \circ u) = \Omega(u') \circ \Omega(u).

Since ΩK′(A′)\Omega_{K'}(A') is an A′A'-module, from Ω(u)\Omega(u) we derive canonically an A′A'-linear mapping

(41)(41)
Ω0(u):ΩK(A)⊗AA′→ΩK′(A′) \Omega_0(u) : \Omega_K(A) \otimes_A A' \to \Omega_{K'}(A')

such that Ω(u)\Omega(u) is the composition of Ω0(u)\Omega_0(u) and the canonical homomorphism iA:ΩK(A)→ΩK(A)⊗AA′i_A : \Omega_K(A) \to \Omega_K(A) \otimes_A A'. For every A′A'-module E′E', there is a commutative diagram

Hom⁡A′(ΩK′(A′),E′)→Hom⁡(Ω0(u),1E′)Hom⁡A′(ΩK(A)⊗AA′,E′)ϕA′↓ϕA∘rA↓DK′(A′,E′)→C(u)DK(A,E) \begin{array}{ccc} \operatorname{Hom}_{A'}(\Omega_{K'}(A'), E') & \xrightarrow{\operatorname{Hom}(\Omega_0(u), 1_{E'})} & \operatorname{Hom}_{A'}(\Omega_K(A) \otimes_A A', E') \\ \phi_{A'} \downarrow & & \phi_A \circ r_A \downarrow \\ D_{K'}(A', E') & \xrightarrow{C(u)} & D_K(A, E) \end{array}

where C(u)C(u) is the mapping D↦D∘uD \mapsto D \circ u (no. 7, Proposition 9) and rAr_A is the canonical isomorphism

Hom⁡(iA,1E′):Hom⁡A′(ΩK(A)⊗AA′,E′)→Hom⁡A(ΩK(A),E′); \operatorname{Hom}(i_A, 1_{E'}) : \operatorname{Hom}_{A'}(\Omega_K(A) \otimes_A A', E') \to \operatorname{Hom}_A(\Omega_K(A), E');

this follows immediately from Proposition 19 and the definition of the isomorphisms ϕA\phi_A and ϕA′\phi_{A'}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 1998, Springer. Not translated.