Bourbaki

Proposition 13

Tag 06AH, permanent. Cite it as [Bourbaki, Tag 06AH].

Algebra, chapter IV, § 1. Polynomials

— Let I\mathscr{I} be the set of irreducible monic polynomials in K[X]K[X]. Let f be a non-zero element of K[X]K[X] and a its leading coefficient; then there exists precisely one family of positive integers (vp)p∈S(v_p)_{p \in \mathscr{S}} with finite support, such that we have a decomposition

f=α∏p∈Spvp. f = \alpha \prod_{p \in \mathscr{S}} p^{v_p}.

It suffices to prove the proposition when ff is monic, that is when α=1\alpha = 1. We shall argue by induction on the degree nn off, the case n=0n = 0 being trivial. Suppose then that n≥1n \geq 1 and that the proposition has been established for all polynomials of degree <n< n.

Let EE be the set of monic polynomials ≠1\neq 1 which divide ff; we have f∈Ef \in E hence EE is not empty and there exists in EE a polynomial gg of least degree. It is clear that gg is irreducible and there exists a monic polynomial hh of degree <n< n such that f=ghf = gh; by the induction hypothesis hh is the product of a finite family of irreducible monic polynomials, hence ff has the same property. This proves the existence of the decomposition (18).

Let us now prove the uniqueness of the decomposition (18). Let (wp)p∈S(w_p)_{p \in \mathscr{S}} be a family of positive integers with finite support, such that f=∏p∈Spwpf = \prod_{p \in \mathscr{S}} p^{w_p}. Since ff is of degree n≥1n \geq 1, there exists p∈Sp \in \mathscr{S} such that wp>0w_p > 0; if we had vp=0v_p = 0, ff would be the product of a family of elements of S\mathscr{S} distinct from pp, hence it would be prime to pp (IV, p. 13, Cor. 6), contrary to the fact that pp divides ff. By the induction hypothesis the polynomial f/pf/p admits a unique decomposition of type (18); hence we conclude the equality wq=vqw_q = v_q for every q∈4q \in \mathbf{4}.

Let ff be a non-zero polynomial in K[X]\mathbf{K}[X]. We shall say that ff has no multiple factors if the exponents vpv_p in the decomposition (18) are all ≤1\leq 1; it comes to the same to say that ff is the product of a finite sequence of pairwise distinct irreducible polynomials, or also that ff is not divisible by the square of any non-constant polynomial of K[X]\mathbf{K}[X].

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2003, Springer. Not translated.