Proposition 13
Tag 06AH, permanent. Cite it as [Bourbaki, Tag 06AH].
Algebra, chapter IV, § 1. Polynomials
— Let be the set of irreducible monic polynomials in . Let f be a non-zero element of and a its leading coefficient; then there exists precisely one family of positive integers with finite support, such that we have a decomposition
It suffices to prove the proposition when is monic, that is when . We shall argue by induction on the degree off, the case being trivial. Suppose then that and that the proposition has been established for all polynomials of degree .
Let be the set of monic polynomials which divide ; we have hence is not empty and there exists in a polynomial of least degree. It is clear that is irreducible and there exists a monic polynomial of degree such that ; by the induction hypothesis is the product of a finite family of irreducible monic polynomials, hence has the same property. This proves the existence of the decomposition (18).
Let us now prove the uniqueness of the decomposition (18). Let be a family of positive integers with finite support, such that . Since is of degree , there exists such that ; if we had , would be the product of a family of elements of distinct from , hence it would be prime to (IV, p. 13, Cor. 6), contrary to the fact that divides . By the induction hypothesis the polynomial admits a unique decomposition of type (18); hence we conclude the equality for every .
Let be a non-zero polynomial in . We shall say that has no multiple factors if the exponents in the decomposition (18) are all ; it comes to the same to say that is the product of a finite sequence of pairwise distinct irreducible polynomials, or also that is not divisible by the square of any non-constant polynomial of .
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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