Bourbaki

Example 6

Tag 06DJ, permanent. Cite it as [Bourbaki, Tag 06DJ].

Algebra, IV, p. 55, § 5. Symmetric tensors and polynomial mappings

Let f∈PolAq(M,N)f \in \mathrm{Pol}_A^q(M, N), let BB be a commutative ring, ρ\rho a homomorphism of BB into AA and M′M' and N′N' the BB-modules derived from MM and NN by means of ρ\rho. Assume that M′M' is free; then f∈PolBq(M′,N′)f \in \mathrm{Pol}_B^q(M', N'): this follows at once from condition (i) of Prop. 13.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 2003, Springer. Not translated.