Bourbaki

Definition 4

Tag 06GL, permanent. Cite it as [Bourbaki, Tag 06GL].

Algebra, chapter V, § 1. Prime fields. Characteristic

— A field K of characteristic exponent q is said to be perfect if we have Kq=KK^q = K. When Kq≠KK^q \neq K, K is called imperfect. By this definition a field is perfect if it is of characteristic 0, or if it is a perfect ring of characteristic p≠0p \neq 0 in the sense of Def. 2. If KK is a field of characteristic p≠0p \neq 0 and (K,u)(K, u) is a perfect closure of KK, then K is a field by Prop. 3 (V, p. 6) and uu is an isomorphism of K onto a subfield of K^\hat{K}. Frequently one identifies KK with its image under uu in K^\hat{K}, so that we have K^=Kp−∞\hat{K} = K^{p^{-\infty}} (Prop. 3). Let K be a field of characteristic 0 ; the characteristic exponent of KK is then 1. By convention the notation xq−fx^{q^{-f}} and Sq−fS^{q^{-f}} is taken to mean x and S respectively (for an element xx of KK and a subset S of KK). In particular we put Kq−∞=KK^{q^{-\infty}} = K and we agree to take the perfect closure of KK to be KK.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 2003, Springer. Not translated.