Bourbaki

Proposition 3

Tag 06H3, permanent. Cite it as [Bourbaki, Tag 06H3].

Algebra, chapter V, § 2. Extensions

— Let F\mathscr{F} be a set of subfields of a field E, directed with respect to the relation ⊂\subset. The union L of the fields of F\mathscr{F} is a field.

For if x and y are two elements of L, there exist two fields R, S of F\mathscr{F} such that x∈R, y∈Sx \in R,\ y \in S; let T be a field of F\mathscr{F} containing R and S; then x∈T, y∈Tx \in T,\ y \in T, hence x+y, xyx + y,\ xy and x−1x^{-1} (if x≠0x \neq 0) belong to T, hence to L.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Nothing.

Transcribed from the printed edition, 2003, Springer. Not translated.