The polynomial Φ3(X)=X2+X+1 is irreducible in Fq[X] if and only if q≡2(mod3). Likewise Φ4(X)=X2+1 is irreducible in Fq[X] if and only if q≡3(mod4) and for Φ5=X4+X3+X2+X+1, the irreducibility condition reads q≡2,3(mod5).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.