Theorem 1
Tag 0735, permanent. Cite it as [Bourbaki, Tag 0735].
Algebra, chapter VII, § 3. Free modules over a principal ideal domain
— Let be a ring such that every left ideal of is projective (II, p. 231, Def. 1) as an -module. Then every submodule of a free left -module is a direct sum of modules isomorphic to ideals of .
Let be a basis for , and let be the coordinate functions corresponding to this basis. Choose a well-ordering (Set Theory, III, p. 153) of and let denote the submodule generated by the , for ; put . The coordinate function maps onto an ideal of ; since is a projective -module, there exists (II, p. 231, Prop. 4) a submodule of , such that the map from into is bijective. Let be the submodule of generated by the , for ; we will show that for all , which will imply that is generated by the family . In fact, suppose for all ; then , for all ; thus there exists such that is a linear combination of finitely many elements , with ; in other words is an element of , for some ; the inductive hypothesis shows that , that is that , and so . It remains to show that the sum of the is direct; now suppose there exists a linear relation , with , where the (all but finitely many of which are zero) are not all zero. Let be the greatest index such that ; since for , we have , so , contradicting the choice of .
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Cited by
- Exercise 24, § 3
- Corollary 2, § 1
- Exercise 20, § 4
- Exercise 2, § 3
- Remark, § 3
- Corollary 1, § 3
- Corollary 2, § 3
- Proposition 8, § 2