— Let Ei(1≤i≤n) and F be topological vector spaces on a non-discrete valued field K. In order that a multilinear mapping f of ∏i=1nEi in F should be continuous in the product space ∏i=1nEi it is sufficient for it to be continuous at (0,0,...,0).
Let (a1,a2,...,an) be an arbitrary point of ∏i=1nEi; we must show that for every neighbourhood W of 0 in F there exist neighbourhoods Vi of 0 in Ei (1≤i≤n) such that the relations zi∈Vi imply
f(a1+z1,a2+z2,...,an+zn)−f(a1,a2,...,an)∈W.
Now, we can write
f(a1+z1,...,an+zn)−f(a1,...,an)=H∑uH
where H varies over the 2n−1 subsets of the set of integers {1,2,...,n}, excluding the set {1,2,...,n} itself, and where uH=f(y1,y2,...,yn), with yi=ai if i∈H and yi=zi if i∈/H. There exist 2n−1 balanced neighbourhoods WH of 0 in F such that ∑HWH⊂W; on the other hand as f is continuous at (0,0,...,0) by hypothesis, there exists in each Ei a neighbourhood Ui of 0 (1≤i≤n) such that the n relations xi∈Ui imply that f(x1,...,xn)∈⋂HWH. As Ui is absorbent, there exists λi=0 in K such that λiai∈Ui. Let λ be an element of K such that ∣λ∣≥∏i∈H∣λi∣−1 for each subset H; we show that the neighbourhoods Vi=λ−nUi, fulfill the required condition. We can write uH=μf(x1,...,xn) where xi∈Ui for 1≤i≤n and μ=λ−np(∏i∈Hλi−1), p being the number of integers of {1,2,...,n} not in H. From the above ∣μ∣≤1, hence uH∈μWH⊂WH since WH is balanced. The proposition is established.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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