Bourbaki

Remark

Tag 07AV, permanent. Cite it as [Bourbaki, Tag 07AV].

Topological Vector Spaces, chapter II, § 1. Semi-norms

— 1) The topology defined by a finite set of semi-norms pip_i (1≤i≤n1 \leq i \leq n) on EE, can be defined by the single semi-norm p=sup⁡1≤i≤npip = \sup_{1 \leq i \leq n} p_i. But a topology defined by an infinite set of semi-norms cannot, in general, be defined by a single semi-norm (III, p. 37, exerc. 2).

2) Let (Ti)i∈I(\mathscr{T}_i)_{i \in I} be a family of topologies on a vector space EE over KK, each of which is defined by a family of semi-norms Γi\Gamma_i. Then the topology defined by the set of semi-norms Γ=⋃i∈IΓi\Gamma = \bigcup_{i \in I} \Gamma_i is the upper bound of the topologies Ti\mathscr{T}_i.

3) If Γ0\Gamma_0 is a set of semi-norms directed by the increasing order relation defined between two semi-norms p,qp, q on EE by « there exists λ>0\lambda > 0 such that p≤λqp \leq \lambda q », then a fundamental system of neighbourhoods of 0, for the topology defined by Γ0\Gamma_0, is obtained by taking the sets V(p,α)V(p, \alpha) where p∈Γ0p \in \Gamma_0 and α>0\alpha > 0. If Γ\Gamma is any set of semi-norms on EE, then a filtered set of semi-norms, defining the same topology as Γ\Gamma, is the set Γ0\Gamma_0 of upper envelopes of all finite families of semi-norms belonging to Γ\Gamma.

4) Even if K=RK = \mathbf{R}, the topology of a topological vector space over KK cannot always be defined by a set of semi-norms (cf. II, p. 24, corollary).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.