Bourbaki

Example

Tag 07BW, permanent. Cite it as [Bourbaki, Tag 07BW].

Topological Vector Spaces, II, p. 13, § 2. Convex sets

\* Let H be a real Hilbert space; in the vector space L(H)\mathscr{L}(H) of continuous endomorphisms of H, the positive hermitian endomorphisms form a proper pointed convex cone; this cone, therefore, defines an order structure compatible with the vector space structure of L(H)\mathscr{L}(H) and for which the relation A⩽BA \leqslant B means that B−AB - A is a positive hermitian endomorphism. \*

For any pointed convex cone P in the vector space E, the set P∩(−P)P \cap (-P) is a vector subspace, H, of E (II, p. 11, cor. 2). The canonical image P′P' of P in E/HE/H is a convex cone and the inverse image of P′P' in E is P. Thus P′∩(−P′)={0}P' \cap (-P') = \{0\}, and P′P' defines an order structure on E/HE/H that is compatible with its vector space structure.

A linear form ff on a preordered vector space E is said to be positive if x⩾0x \geqslant 0 in E implies f(x)⩾0f(x) \geqslant 0. Or, alternatively, if the convex cone P of elements ⩾0\geqslant 0 in E is contained in the half space of those xx for which f(x)⩾0f(x) \geqslant 0. Clearly, in the dual E∗E^* to E, the set of positive linear forms is a pointed convex cone.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.