Bourbaki

Lemma 1

Tag 07M8, permanent. Cite it as [Bourbaki, Tag 07M8].

Topological Vector Spaces, chapter III, § 2. Bornological spaces

— Let G be a semi-normed space, p its semi-norm, and u a linear mapping from G into E. The following conditions are equivalent :

(i) u is continuous ; (ii) the image of the unit ball of G under u is bounded in E ; (iii) for every sequence (xn)(x_n) of points of G tending to 0, the sequence (u(xn))(u(x_n)) is bounded in E.

It is immediate that (i) implies (ii) (III, p. 4, cor. 1) and that (ii) implies (iii). Let V be a neighbourhood of 0 in E ; if u−1(V)u^{-1}(V) is not a neighbourhood of 0 in G, then there exists a sequence (yn)(y_n) of points of G−u−1(V)G - u^{-1}(V) such that p(yn)≤1n2p(y_n) \leq \frac{1}{n^2}. Hence the sequence xn=nynx_n = n y_n tends to 0 in G and u(xn)∉nVu(x_n) \notin nV, which implies that the sequence (u(xn))(u(x_n)) is not bounded. Therefore (iii) implies (i).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.