Bourbaki

Theorem 1

Tag 07UV, permanent. Cite it as [Bourbaki, Tag 07UV].

Topological Vector Spaces, IV, p. 28, § 4. Strict morphisms of Fréchet spaces

*Let E and F be two Fréchet spaces and u a continuous linear mapping from E into F. The following conditions are equivalent :

a) uu is a strict morphism. b) uu is a strict morphism for the weakened topologies. c) The image of uu is closed in F. d) tu^t u is a strict morphism from F′F' into E′E' for the weak topologies. e) The image of tu^t u is closed in E′E' for the weak topology σ(E′,E)\sigma(E', E). f) The image of tu^t u is closed in E′E' for the strong topology β(E′,E)\beta(E', E). g) tu^t u is a strict morphism from Fc′F'_c into Ec′E'_c (the duals endowed with the topology of compact convergence).

The equivalence of a), b) and e) follows from prop. 3 of IV, p. 28 and the remark preceding it. That of a) and c) is precisely cor. 3 of I, p. 19. The remark of IV, p. 28, also shows that d) is equivalent to the fact that, the image of uu is closed for the weakened topology σ(F,F′)\sigma(F, F') of F; the equivalence of c) and d) then follows from prop. 2 of IV, p. 4.

We now prove the equivalence of e) and f). It is enough to prove that f) implies e). Suppose that the image of tu^t u is closed for β(E′,E)\beta(E', E) in E′E'. On account of the Banach-Dieudonné theorem (IV, p. 25, cor. 2), it is enough to prove that for every convex balanced neighbourhood U of 0 in E, the intersection B=tu(F′)∩UB = ^t u(F') \cap U is compact for σ(E′,E)\sigma(E', E). The strong dual Eb′E'_b of the Fréchet space E is complete (IV, p. 22, prop. 2), hence the closed subset B of Eb′E'_b is complete, and so the normed space EB′E'_B is complete (III, p. 8, corollary). Let (Vn)(V_n) be a decreasing sequence forming a fundamental system of neighbourhoods of 0 in F. Then F′F' is the union of sets C=Vn∘C = V_n^\circ which are compact for σ(F′,F)\sigma(F', F), hence EB′=⋃nBnE'_B = \bigcup_n B_n, with Bn=EB′∩tu(Cn)B_n = E'_B \cap ^t u(C_n). Since EB′E'_B is a Baire space, and each of the sets BnB_n is convex balanced and closed, there exists a real number r>0r > 0 and an integer nn such that B⊂r.BnB \subset r.B_n. Then we have B=U∘∩tu(r.Cn)B = U^\circ \cap {}^t u(r.C_n); since the sets U∘U^\circ and r.Cnr.C_n are compact and tu{}^t u is continuous for the weak topologies, BB is compact for σ(E′,E)\sigma(E', E). This completes the proof of the equivalence of e) and f).

Finally the equivalence of g) and the preceding conditions follows from prop. 18 of GT, X, § 2, No. 10 and the following lemma.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.