Theorem 1
Tag 07UV, permanent. Cite it as [Bourbaki, Tag 07UV].
Topological Vector Spaces, IV, p. 28, § 4. Strict morphisms of Fréchet spaces
*Let E and F be two Fréchet spaces and u a continuous linear mapping from E into F. The following conditions are equivalent :
a) is a strict morphism. b) is a strict morphism for the weakened topologies. c) The image of is closed in F. d) is a strict morphism from into for the weak topologies. e) The image of is closed in for the weak topology . f) The image of is closed in for the strong topology . g) is a strict morphism from into (the duals endowed with the topology of compact convergence).
The equivalence of a), b) and e) follows from prop. 3 of IV, p. 28 and the remark preceding it. That of a) and c) is precisely cor. 3 of I, p. 19. The remark of IV, p. 28, also shows that d) is equivalent to the fact that, the image of is closed for the weakened topology of F; the equivalence of c) and d) then follows from prop. 2 of IV, p. 4.
We now prove the equivalence of e) and f). It is enough to prove that f) implies e). Suppose that the image of is closed for in . On account of the Banach-Dieudonné theorem (IV, p. 25, cor. 2), it is enough to prove that for every convex balanced neighbourhood U of 0 in E, the intersection is compact for . The strong dual of the Fréchet space E is complete (IV, p. 22, prop. 2), hence the closed subset B of is complete, and so the normed space is complete (III, p. 8, corollary). Let be a decreasing sequence forming a fundamental system of neighbourhoods of 0 in F. Then is the union of sets which are compact for , hence , with . Since is a Baire space, and each of the sets is convex balanced and closed, there exists a real number and an integer such that . Then we have ; since the sets and are compact and is continuous for the weak topologies, is compact for . This completes the proof of the equivalence of e) and f).
Finally the equivalence of g) and the preceding conditions follows from prop. 18 of GT, X, § 2, No. 10 and the following lemma.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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