Bourbaki

Corollary 2

Tag 07XS, permanent. Cite it as [Bourbaki, Tag 07XS].

Topological Vector Spaces, chapter V, § 1. Prehilbertian spaces and hilbertian spaces

For every x,yx, y in E\mathbf{E}, we have

∥pH(x)−pH(y)∥≤∥x−y∥. \| p_{\mathbf{H}}(x) - p_{\mathbf{H}}(y) \| \leq \| x - y \| .
In particular, the mapping pHp_{\mathbf{H}} from E\mathbf{E} into H\mathbf{H} is continuous.

Let x,yx, y be two points of E\mathbf{E}. Put a=pH(x)−x,b=pH(y)−pH(x),c=y−pH(y)a = p_{\mathbf{H}}(x) - x, b = p_{\mathbf{H}}(y) - p_{\mathbf{H}}(x), c = y - p_{\mathbf{H}}(y). By formula (15) (V, p. 10) we have R⟨a∣b⟩≥0\mathscr{R} \langle a|b \rangle \geq 0 and R⟨c∣b⟩≥0\mathscr{R} \langle c|b \rangle \geq 0. We also have a+b+c=y−xa + b + c = y - x, which gives,

∥x−y∥2=∥a+b+c∥2=∥b∥2+∥a+c∥2+2R⟨a∣b⟩+2R⟨c∣b⟩ \| x - y \|^{2} = \| a + b + c \|^{2} = \| b \|^{2} + \| a + c \|^{2} + 2 \mathscr{R} \langle a|b \rangle + 2 \mathscr{R} \langle c|b \rangle
≥∥b∥2=∥pH(x)−pH(y)∥2. \geq \| b \|^{2} = \| p_{\mathbf{H}}(x) - p_{\mathbf{H}}(y) \|^{2} .
This proves corollary 2.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.