Bourbaki

Proposition 1

Tag 080X, permanent. Cite it as [Bourbaki, Tag 080X].

Topological Vector Spaces, chapter V, § 4. Some classes of operators in hilbertian spaces

— Let E and F be two hilbertian spaces. For every mapping u∈L(E;F)u \in \mathscr{L}(E; F), there exists a unique mapping u∗∈L(F;E)u^* \in \mathscr{L}(F; E) such that

⟨u(x)∣y⟩F=⟨x∣u∗(y)⟩E \langle u(x)|y \rangle_F = \langle x|u^*(y) \rangle_E

for all x∈Ex \in E and all y∈Fy \in F. The mapping u↦u∗u \mapsto u^* from L(E,F)\mathscr{L}(E, F) into L(F;E)\mathscr{L}(F; E) is bijective, isometric and semi-linear (with respect to the automorphism ξ↦ξ‾\xi \mapsto \overline{\xi} of K).

Let S(E,F)\mathscr{S}(E, F) be the space of all continuous sesquilinear forms on E×FE \times F, endowed with the norm

∥Φ∥=sup⁡∥x∥≤1,∥y∥≤1∣Φ(x,y)∣. \| \Phi \| = \sup_{\|x\| \leq 1, \|y\| \leq 1} |\Phi(x, y)| .

We define the space S(F,E)\mathscr{S}(F, E) similarly. We defined (V, p. 16, cor. 2) a Banach space isomorphism from L(E;F)\mathscr{L}(E; F) onto S(F,E)\mathscr{S}(F, E), denoted by u↦Φuu \mapsto \Phi_u and characterized by

Φu(y,x)=⟨y∣u(x)⟩F(x∈E, y∈F). \Phi_u(y, x) = \langle y|u(x) \rangle_F \quad (x \in E, \ y \in F) .

In an analogous way we define an isomorphism from L(F,E)\mathscr{L}(F, E) onto S(E,F)\mathscr{S}(E, F). Finally we define a mapping Φ↦Φ∗\Phi \mapsto \Phi^* from S(F,E)\mathscr{S}(F, E) onto S(E,F)\mathscr{S}(E, F) by

Φ∗(x,y)=Φ(y,x)‾(x∈E, y∈F). \Phi^*(x, y) = \overline{\Phi(y, x)} \quad (x \in E, \ y \in F) .

This mapping is bijective, semi-linear and isometric. But formula (1) translates as Φu∗=(Φu)∗\Phi_{u^*} = (\Phi_u)^*, hence the proposition.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Transcribed from the printed volume. Not translated.